 Subtract the number of decimal places in the divisor from the number of decimal places in the dividend, and point off as many decimal places in the quotient as there are units in the remainder thus found.  Shop Mathematics ...: Shop arithmetic - Σελίδα 36των Earle Bertram Norris, Kenneth Gardner Smith, Ralph Thurman Craigo - 1912Πλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Stoddard A. Felter - 1864 - 412 σελίδες
...division, making the number of decimal places in the dividend at least equal to those in the divisor ; then subtract the number of decimal places in the divisor from the number of decimal places in the dividend, and the remainder will denote the number of DECIMAL TRACTIONS. decimal... | |
 | Charles Elsee - 1866 - 300 σελίδες
...-ooi, -76. (8) The square of -125 x cube of -32. 38. — Division. RULE. Divide as in whole numbers : subtract the number of decimal places in the divisor from the number in the dividend, the remainder will be the number in the quotient But if the number of decimal places in the divisor... | |
 | George Ricks - 1881 - 288 σελίδες
...therefore add ciphers to make as many decimal places as there are in the divisor. Then subtracting the number of decimal places in the divisor from the number in the dividend we get nothing. That is, there are no decimal places in the quotient. Ex. 4. Divide -0064 by 16. 16)-0064(-0004... | |
 | 1885 - 630 σελίδες
...decimal point in dividing one decimal by another. Divide '378 by 262*5, an(^ 37'8 by •0002625. Rule : Subtract the number of decimal places in the divisor from the number in the dividend, and mark off the difference in the quotient. If the number in the divisor exceeds the number in the dividend... | |
 | 1893 - 376 σελίδες
...as in the divisor, then divide. 4. To flnd out how many decimal places to point off in the quotient, subtract the number of decimal places in the divisor from the number in the dividend. 5. If there are not enough figures in the quotient to point off the right number, prefix enough ciphers... | |
 | Christian Brothers - 1888 - 484 σελίδες
...gives a final quotient of 152. Now, since the dividend is the product of the quotient by the divisor, we subtract the number of decimal places in the divisor from the number in the dividend, and the remainder will be the number required for the quotient. Counting the three ciphers annexed, we... | |
 | 1897 - 366 σελίδες
...by annexing ciphers the number of decimal places in the divisor. Divide exactly as in whole numbers. Subtract the number of decimal places in the divisor from the number of decimal places in the dividend, and point off as many decimal places in the quotient as there are... | |
 | 1897 - 672 σελίδες
...annexing ciphers) the number of decimal places in the divisor. Divide exactly as in whole numbers. Subtract the number of decimal places in the divisor from the number of decimal places in the dividend, and point off as many decimal places in the quotient as there are... | |
 | International Correspondence Schools - 1897 - 346 σελίδες
...annexing ciphers) the number of decimal places in the divisor. Divide exactly as in whole numbers. Subtract the number of decimal places in the divisor from the number of decimal places in the dividend, and point off 'as many decimal places in the quotient as there are... | |
 | International Correspondence Schools - 1898 - 518 σελίδες
...annexing ciphers) the number of decimal places in the divisor. Divide exactly as in whole numbers. Subtract the number of decimal places in the divisor from the number of decimal places in the dividend, and point off as many decimal i i places in the quotient as thcre... | |
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