III. Elimination by Comparison. 115. Take again the equations, 5x+7y=43, 11x+9y=69. Finding the value of x from the first equation, we have and finding the value of x from the second, we obtain Let these two values of x be placed equal to each other, and we have This method of elimination is called the method by comparison, for which we have the following rule: Find from each equation the value of the same unknown quantity to be eliminated. Place these values equal to each other. Exercises. Find by the last rule the values of x and y from the following equations: 1. 3x+2+6=42, and y-2=143. 4 = + 1 x+5, and ≈+= y − 34. Ans. x=2, y=9. x y y-2, and += = x — 13. 9. 4y=x+18, and 27 - y = x + y +4. 2 116. Having explained the principal methods of elimination, we shall add a few examples which may be solved by any one of them; and often, indeed, it may be advantageous to employ them all, even in the same example. 1. What fraction is that to the numerator of which if 1 be added the value will be, but if 1 be added to its denominator the value will be 2. A market-woman bought a certain number of eggs at 2 for a penny, and as many others at 3 for a penny; and, having sold them altogether at the rate of 5 for 2 pence, she found that she had lost 4 pence. How many of both kinds did she buy? |