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Σελίδα 214
Ans . 31 rods in length , and 19 in breadth . Solved by PROBLEM VI , page 183 .
2. A tract of land is to be laid out in form of an equal square , and to be enclosed
with a post and rail fenice 5 rails high ; so that each rod of fence shall contain 10
...
Ans . 31 rods in length , and 19 in breadth . Solved by PROBLEM VI , page 183 .
2. A tract of land is to be laid out in form of an equal square , and to be enclosed
with a post and rail fenice 5 rails high ; so that each rod of fence shall contain 10
...
Σελίδα 221
Or , in measuring boards , you may multiply the length in feet by the breadth in
inches , and divide by 12 , the quotient will give the answer in square feet , & c .
Thus , in the foregoing example , 21x18 + 12 = 31,5 as before . 4. If a board be 8
...
Or , in measuring boards , you may multiply the length in feet by the breadth in
inches , and divide by 12 , the quotient will give the answer in square feet , & c .
Thus , in the foregoing example , 21x18 + 12 = 31,5 as before . 4. If a board be 8
...
Σελίδα 223
1 6-1,5 and 1,5X1,5X1,5 = 3,375 solid feet . Ans . Or , 18x18x18-5832 solid
inches , and 1 = 3,375 2. Suppose a cellar to be dug that shall contain 12 feet
every way , in length , breadth and depth ; how many solid feet of earth must be
taken out ...
1 6-1,5 and 1,5X1,5X1,5 = 3,375 solid feet . Ans . Or , 18x18x18-5832 solid
inches , and 1 = 3,375 2. Suppose a cellar to be dug that shall contain 12 feet
every way , in length , breadth and depth ; how many solid feet of earth must be
taken out ...
Σελίδα 224
When the breadth and thickness of a piece of timber are given in inches , to find
how much in length will make a solid foot . RULE . Divide 1728 by the product of
the breadth and depth , and the quotient will be the length making a solid foot .
When the breadth and thickness of a piece of timber are given in inches , to find
how much in length will make a solid foot . RULE . Divide 1728 by the product of
the breadth and depth , and the quotient will be the length making a solid foot .
Σελίδα 225
X1,5 Square 2,25X , 7854 = 1,76715 area of the base . x 20 length . Ans . 35,
54300 solid content . Or , 18 inches . 18 inches . EXAMPLE . 324 X , 7854 = 254,
4696 inches , area of the base . 20 length in feet . 144 ) 5089,3920 ( 85,345 solid
feet ...
X1,5 Square 2,25X , 7854 = 1,76715 area of the base . x 20 length . Ans . 35,
54300 solid content . Or , 18 inches . 18 inches . EXAMPLE . 324 X , 7854 = 254,
4696 inches , area of the base . 20 length in feet . 144 ) 5089,3920 ( 85,345 solid
feet ...
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