# The First Part of the United States Arithmetic Designed for Schools

E.C. & J. Biddle, 1857 - 112 σελίδες

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### Περιεχόμενα

 Notation and Numeration 13 Subtraction 20 Multiplication 28 Division 38 Compound Addition 53
 Compound Subtraction 71 Multiplication of Federal Money 83 Compound Multiplication 91 Division of Federal Money 97 Miscellaneous Exercises Oral 105

### Δημοφιλή αποσπάσματα

Σελίδα 61 - TABLE. 4 nails, (na.) or 9 inches, make 1 quarter, marked qr. 4 quarters, or 36 inches, - 1 yard, - - - - yd. 3 quarters, ------ 1 ell Flemish, - - E. Fl 5 quarters, ------ 1 ell English, - - EE 6 quarters, ------ 1 ell French, - - E. Fr 27.
Σελίδα 47 - Multiply the last remainder by the preceding divisor, or last but one, and to the product add the preceding remainder ; multiply this sum by the next preceding divisor, and to the product add the next preceding remainder ; and so on, till you have gone backward through all the divisors and remainders to the first.
Σελίδα 15 - ... any number divided by 9, will leave the same remainder as the sum of its figures, or digits, divided by 9, which may be thus demonstrated.
Σελίδα 62 - LIQUID MEASURE 4 gills (gi.) = 1 pint (pt.) 2 pints = 1 quart (qt...
Σελίδα 54 - Scale: 4 farthings (far.) = 1 penny (d.); 12 pence = 1 shilling (s.) ; 20 shillings — 1 pound (£). 156.
Σελίδα 34 - The reason of this method is obvious ; for any number multiplied by the component parts of another, must give the same product as if it were multiplied by that number...
Σελίδα 63 - ... ..1 gallon, gal 36 gallons " .1 barrel, bar. 54 gallons
Σελίδα 40 - The logarithm of the product of two or more numbers is equal to the sum of the logarithms of those numbers. Let a denote the base of the system ; also, let m and n be any two numbers, and x and y their logarithms. Then, by the definition of logarithms, we have ax=m, (1.) a?in.
Σελίδα 91 - Carry the integers, thus found, to the product of the next higher denomination, with which proceed as before ; and so on, through all the denominations -to the highest; then this product, together with the several remainders, taken as one number, will be the whole amount required.
Σελίδα 49 - Divide the number by any prime number which will divide it without any remainder ; then divide the quotient in the same way, and so continue until a quotient is obtained which is a prime. Then will the successive divisors, together with the last quotient, be the prime factors required.