The Principles of the Solution of the Senate-house 'riders,' Exemplified by the Solution of Those Proposed in the Earlier Parts of the Examinations of the Years 1848-1851Macmillan & Company, 1851 - 116 σελίδες |
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Αποτελέσματα 1 - 5 από τα 15.
Σελίδα 13
... ellipse is equal to a given line , shew that the axis - major is equal to the same line . ( B ) . Shew that the axis - major is greater than any other diameter . Let PCP ' ( fig . 16 ) be any diameter . Join P and P ' with the foci ...
... ellipse is equal to a given line , shew that the axis - major is equal to the same line . ( B ) . Shew that the axis - major is greater than any other diameter . Let PCP ' ( fig . 16 ) be any diameter . Join P and P ' with the foci ...
Σελίδα 14
... ellipse if PU be a tangent at P , meeting the minor axis produced in U , and PN be drawn perpen- dicular to the minor axis , then CN : CB :: CB : CU . ( B ) . If a series of ellipses be described having the same major axis , the ...
... ellipse if PU be a tangent at P , meeting the minor axis produced in U , and PN be drawn perpen- dicular to the minor axis , then CN : CB :: CB : CU . ( B ) . If a series of ellipses be described having the same major axis , the ...
Σελίδα 15
... ellipse intersect the tangent in the circumference of a circle having the axis - major as diameter . ( B. ) Employ this proposition to find the locus of the intersection of a pair of tangents at right angles to each other . ( C ) ...
... ellipse intersect the tangent in the circumference of a circle having the axis - major as diameter . ( B. ) Employ this proposition to find the locus of the intersection of a pair of tangents at right angles to each other . ( C ) ...
Σελίδα 16
... ellipse at the ends of conjugate diameters are equal . ( B ) . Prove that such parallelograms have the least area of all which circumscribe the ellipse . Let TTTT ( fig . 21 ) be a parallelogram circumscribing an ellipse at the ...
... ellipse at the ends of conjugate diameters are equal . ( B ) . Prove that such parallelograms have the least area of all which circumscribe the ellipse . Let TTTT ( fig . 21 ) be a parallelogram circumscribing an ellipse at the ...
Σελίδα 17
... ellipse , this constant area is the least . 1850. ( A ) . In the hyperbola the rectangle under the lines intercepted between the centre and the intersections of the axis with the ordinate and tangent respectively , is equal to the ...
... ellipse , this constant area is the least . 1850. ( A ) . In the hyperbola the rectangle under the lines intercepted between the centre and the intersections of the axis with the ordinate and tangent respectively , is equal to the ...
Άλλες εκδόσεις - Προβολή όλων
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
AC² AN.NM Arithmetic arithmetical progression axis bisects body C₁ Cambridge centre of gravity chord CHURCHILL BABINGTON circle cloth cone Conic Sections conjugate hyperbola constant curvature curve cycloid describe diameter direction directrix distance drawn Edition ellipse equations equilibrium Fellow of St fluid focus geometrical given point Hence horizontal hyperbola inches inclined inscribed John's College joining latus-rectum least common multiple Lemma length locus meet mirror move number of seconds oscillation parabola parallel parallelogram particle perpendicular plane polygon pressure prop proportional proposition prove pullies quadrilateral quantity radius ratio rays rectangle refraction right angles sewed shew sides specific gravity spherical square straight line string surface tan² tangent triangle ABC Trinity College tube V₁ vary vertex vertical W₁ weight
Δημοφιλή αποσπάσματα
Σελίδα 4 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Σελίδα 6 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.
Σελίδα 11 - AB is a diameter, and P any point in the circumference of a circle; AP and BP are joined and produced if necessary ; if from any point C of AB, a perpendicular be drawn to AB meeting AP and .BP in points D and E respectively, and the circumference of the circle in a point F, shew that CD is a third proportional of CE and CF.
Σελίδα 9 - IF the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Σελίδα 4 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.