The Principles of the Solution of the Senate-house 'riders,' Exemplified by the Solution of Those Proposed in the Earlier Parts of the Examinations of the Years 1848-1851Macmillan & Company, 1851 - 116 σελίδες |
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Σελίδα 44
... pressure acts upon . Considering the rope ( since it is long ) as nearly parallel to the direction of the stream , we shall have two forces , viz . the tension of the rope and the pressure of the water perpendicular to the side of the ...
... pressure acts upon . Considering the rope ( since it is long ) as nearly parallel to the direction of the stream , we shall have two forces , viz . the tension of the rope and the pressure of the water perpendicular to the side of the ...
Σελίδα 47
... pressure ( R ) at the hinge B or the rod CD must act along AB ; for if it does not , the equal reaction upon the rod AB would make it revolve about A , and equilibrium would not exist . We have now the rigid body CD acted on by two ...
... pressure ( R ) at the hinge B or the rod CD must act along AB ; for if it does not , the equal reaction upon the rod AB would make it revolve about A , and equilibrium would not exist . We have now the rigid body CD acted on by two ...
Σελίδα 50
... pressure of two smooth surfaces in contact acts along the common normal to the surfaces at the point of contact ... pressures ( which act in these lines ) exerted on the two given disks , will tend to push them away from 4 , and 1 ...
... pressure of two smooth surfaces in contact acts along the common normal to the surfaces at the point of contact ... pressures ( which act in these lines ) exerted on the two given disks , will tend to push them away from 4 , and 1 ...
Σελίδα 56
... pressure upon the plane ? Let R be the pressure on the plane . The moving force upon the given weight 10 lbs . R , = ( mass ) × ( acceleration per second ) , by the third law of motion , 10 10 , g 100 .lbs .; 32.2 100 therefore R = 10 ...
... pressure upon the plane ? Let R be the pressure on the plane . The moving force upon the given weight 10 lbs . R , = ( mass ) × ( acceleration per second ) , by the third law of motion , 10 10 , g 100 .lbs .; 32.2 100 therefore R = 10 ...
Σελίδα 57
... pressure P in the line of projection : find the velocity of the body at any time . 19 27 ( B ) . A train of ... pressures P , P , ... respectively ; find the conditions in order that the bodies may continue to move with equal velocities ...
... pressure P in the line of projection : find the velocity of the body at any time . 19 27 ( B ) . A train of ... pressures P , P , ... respectively ; find the conditions in order that the bodies may continue to move with equal velocities ...
Άλλες εκδόσεις - Προβολή όλων
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2018 |
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2015 |
Συχνά εμφανιζόμενοι όροι και φράσεις
AC² AN.NM Arithmetic arithmetical progression axis bisects body C₁ Cambridge centre of gravity chord CHURCHILL BABINGTON circle cloth cone Conic Sections conjugate hyperbola constant curvature curve cycloid describe diameter direction directrix distance drawn Edition ellipse equations equilibrium Fellow of St fluid focus geometrical given point Hence horizontal hyperbola inches inclined inscribed John's College joining latus-rectum least common multiple Lemma length locus meet mirror move number of seconds oscillation parabola parallel parallelogram particle perpendicular plane polygon pressure prop proportional proposition prove pullies quadrilateral quantity radius ratio rays rectangle refraction right angles sewed shew sides specific gravity spherical square straight line string surface tan² tangent triangle ABC Trinity College tube V₁ vary vertex vertical W₁ weight
Δημοφιλή αποσπάσματα
Σελίδα 4 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Σελίδα 6 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.
Σελίδα 11 - AB is a diameter, and P any point in the circumference of a circle; AP and BP are joined and produced if necessary ; if from any point C of AB, a perpendicular be drawn to AB meeting AP and .BP in points D and E respectively, and the circumference of the circle in a point F, shew that CD is a third proportional of CE and CF.
Σελίδα 9 - IF the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Σελίδα 4 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.