Εικόνες σελίδας
PDF
Ηλεκτρ. έκδοση

is equal to DE, and BE to AD; AB, BE are equal to ED, Book XI. DA: and in the triangles ABE, EDA, the base AE is common; therefore the angle ABE is equal to the angle EDA: c 8. 1. But ABE is a right angle: therefore EDA is also a right angle, and ED perpendicular to DA: But it is also perpendicular to each of the two BD, DC: Wherefore ED is at right angles to each of the three straight lines BD, DA, DC in the point in which they meet: Therefore these three straight lines are all in the same plane d: but AB is in the plane in d 5. 11. which are BD, DA, because any three straight lines which meet one another are in one planee: Therefore AB, BD, e 2. 11. DC are in one plane: And each of the angles ABD, BDC is a right angle; therefore AB is parallel to CD. Where- f 28. 1. fore, “ if two straight lines,&c. Q. E. D.

PROP. VII. THEOR.

If two straight lines be parallel, the straight line See N. drawn from any point in the one to any point in the other, is in the same plane with the parallels.

Let AB, CD be parallel straight lines, and take any point E in the one, and the point F in the other : The straight line which joins E and F is in the same plane with the parallels.

If not, let it be, if possible, above the plane, as EGF; and in the plane ABCD in which the parallels are, draw the A E

B straight line EHF from E to F; and since EGF also is a straight

G line, the two straight lines EHF,

H EGF include a space between them, which is impossible a.

a 10.Ax.l. Therefore, the straight line join

F D ing the points E, F is not above the plane in which the parallels AB, CD are, and is therefore in that plane. Wherefore, " if two straight lines,&c. Q. E. D.

C

PROP. VIII. THEOR.

If two straight lines are parallel, and one of them See N. is at right angles to a plane ; the other also is at right angles to the same plane.

N

Book XI. Let AB, CD be two parallel straight lines, and let one of

them AB be at right angles to a plane; the other CD is also at right angles to the same plane.

Let AB, CD meet the plane in the points B, D, and join a 7. 11. BD: Therefore 2 AB, CD, BD are in one plane. In the

plane to which AB is at right angles, draw DE at right angles to BD, and make DE equal to AB, and join BE, AE, AD. And because AB is perpendicular to the plane, it is

perpendicular to every straight line which meets it, and is in b 3. def. 11. that plane 6: Therefore, each of the angles ABD, ABE is a

right angle: And because the straight line BD meets the pa

rallel straight lines AB, CD, the angles ABD, CDB are toc 29. 1.

gether equal to two right angles : and ABD is a right an-
gle: therefore also, CDB is a right angle, and CD perpendi-
cular to BD: And because AB is equal to DE, and BD com-
mon, the two AB, BD are equal to the
two ED, DB, and the angle ABD is

с equal to the angle EDB, because each

А
of them is a right angle: therefore the
d 4. 1.

base AD is equal to the base BE:
Again, because AB is equal to DE,
and BE to AD: the two AB, BE are
equal to the two ED, DA; and the

B
base A Eis common to the two triangles

ABE, EDA; wherefore, the angle e 8. I.

ABE is equal to the angle EDA :
And ABE is a right angle; and there-
fore EDA is a right angle and ED

perpendicular to DA: But it is also perpendicular to BD; f4. 11, therefore ED is perpendicular f to the plane which passes g 3. def. 11. through BD, DA, and makes right angles & with every straight

line meeting it in that plane: But DC is in the plane passing through BD, DA, because all three are in the plane in which are the parallels AB, CD: Wherefore ED is at right angles to DC; and therefore CD is at right angles to DE; but CD is also at right angles to DB; CD then is at right angles to the two straight lines DE, DB in the point of their intersection D; and therefore is at right angles to the plane passing through DE, DB, which is the same plane to which AB is at right angles. Therefore, “ if two straight lines,” &c. Q. E. D.

Book XI.

PROP. IX. THEOR.

Two straight lines which are each of them parallel to the same straight line, though not both in the same plane with it, are parallel to one another.

Let AB, CD be each of them parallel to EF, and not in the same plane with it; AB is parallel to CD.

In EF take any point G, from which draw in the plane passing through EF, AB, the straight line GH at right angles to EF; and in the plane passing through EF, CD, draw GK at right angles to the same EF. And because EF is A H perpendicular both to GH and

-B GK, EF is perpendicular a to

a 4. 11. the plane HGK passing through

G them: And EF is parallel to E

F AB; therefore AB is at right angles to the plane HGK. For

b 8. ll. the same reason, CD is likewise C K D at right angles to the plane HGK. Therefore AB, CD are each of them at right angles to the plane HGK. But two straight lines, which are at right angles to the same plane, are parallel to one another. Therefore AB is parallel to CD. c 6. Ji. Wherefore, two straight lines,&c. Q. E. D.

PROP. X. THEOR.

If two straight lines meeting one another be parallel to two others that meet one another, though not in the same plane with the first two; the first two and the other two shall contain equal angles,

Let the two straight lines AB, BC, which meet one another be parallel to the two straight lines DE, EF that meet one another, and are not in the same plane with AB, BC. The angle ABC is equal to the angle DEF. Take BĀ, BC, ED, EF, all equal to one another; and join

Book XI. AD, CF, BE, AC, DF; because BA is equal and parallel to ED, therefore AD is a both equal and

B a 33. I. parallel to BE. For the same reason,

CF is equal and parallel to BE. There-
fore AD and CF are each of them A

С
equal and parallel to BE. But straight
lines that are parallel to the same

straight line, though not in the same b 9. 11. plane with it, are parallelo to one

another: Therefore ÁD is parallel to c I. Ax.l. CF; and it is equal< to it, and AC, E DF join them towards the same parts; D

F. and therefore a AC is equal and parallel to DF. And because AB, BC are

equal to DE, EF, and the base AC to the base DF; the d 8. 1. angle ABC is equal d to the angle DEF. Therefore, if two

straight lines,&c. Q. E. D.

PROP. XI. PROB.

To draw a straight line perpendicular to a plane, from a given point above it.

Let A be the given point above the plane BH; it is required to draw from the point A a straight line perpendicular to the plane BH.

In the plane draw any straight line BC, and from the point a 12. 1. A draw a AD perpendicular to BC. If then AD be also per

pendicular to the plane BH, the thing required is already done; but if it be not, from the

A b 11 1. point D drawb in the plane BH,

the straight line DĖ, at right E
angles to BC; and from the point
A draw AF perpendicular to G

H c 31. 1. DE; and through F draw o GH

parallel to BC: And because BC

is at right angles to ED and DA, d 4. 11.

BC is at right anglesd to the
plane passing through ED, DA. B D C
And GH is parallel to BC; but

if two straight lines are parallel, and one of them is at right e 8. 11. angles to a plane, the other is at right angles to the same

plane; wherefore GH is at right angles to the plane through f 3. def. 11. ED, DA, and is perpendicular f to every straight line meeting

it in that plane. "But AF, which is in the plane through ED, DA meets it: Therefore GH is perpendicular to AF; and Book XI. consequently AF is perpendicular to GH; and AF is also perpendicular to DE: Therefore AF is perpendicular to each of the straight lines GH, DE. But if a straight line stands at right angles to each of two straight lines in the point of their intersection, it is also at right angles to the plane passing through them 8. But the plane passing through ED, GH, is g 4. 11. the plane BH: therefore AF is perpendicular to the plane BH: consequently, from the given point A, above the plane BH, the straight line AF is drawn perpendicular to that plane: Which was to be done.

[blocks in formation]

To erect a straight line at right angles to a given plane, from a given point in the plane.

a 11. 11. b 31. 1.

Let A be the point given in the plane; it is required to erect a straight line from the point A at right angles to the plane.

D

B From any point B above the plane draw a BC perpendicular to it; and from A draw. AD parallel to BC. Because, therefore, AD, CB are two parallel straight lines, and one of them

A BC is at right angles to the given plane,

С the other AD is also at right angles to it. Therefore a straight line has been erected at right angles to a given plane from a point given in it. Which was to be done.

c 8. 11.

PROP. XIII. THEOR.

From the same point in a given plane, there cannot be two straight lines at right angles to the plane, upon the same side of it: And there can be but one perpendicular to a plane from a point above the plane.

For, if it be possible, let the two straight lines AB, AC, be at right angles to a given plane from the same point A in the plane, and upon the same side of it; and let a plane pass through BA, AC; the common section of this plane with the

« ΠροηγούμενηΣυνέχεια »