 | John Radford Young - 1832 - 408 σελίδες
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term of the root, subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. For (by Art. 37), the cube of a + b is a3 + 3a2¿... | |
 | John Radford Young - 1839 - 332 σελίδες
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term of the root, subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. For (by Art. 37,) the cube of a+b is a»+ 3a2¿>... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 σελίδες
...right ; add together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under... | |
 | James Bates Thomson - 1848 - 434 σελίδες
...the right of the partial divisor; multiply the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring doum the next period for a neut dividend. IV. Double the root already found for a new partial divisor,... | |
 | Rufus Putnam - 1849 - 276 σελίδες
...and bring down the next period for a dividend. 4. Multiply the complete divisor by the last figure in the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. If the product should exceed the dividend, diminish the last... | |
 | Benjamin Greenleaf - 1852 - 348 σελίδες
...divisor''s place, and the divisor will be completed. Multiply the complete divisor by the last term of the root; subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. EXAMPLES. 1. Find the cube root of a 3 +3a2J-|-3a6... | |
 | Chambers W. and R., ltd - 1854 - 152 σελίδες
...together, forming the complete divisor, 0436. EXTRACTION OF THE CUBE ROOT. 4. Multiply the complete divisor by the last figure of the root ; subtract the product from the dividend ; and to any remainder, annex the next period of thrce figures, to form a new dividend. 5. Form a new DivisoRas... | |
 | Elias Loomis - 1856 - 280 σελίδες
...figure ; annex the result both to the root and the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring doivn the next period for a new dividend. If the product should be greater than the dividend, diminish... | |
 | Joseph Ray - 1857 - 348 σελίδες
...quotient in the root and also on the right of the divisor. 4. Multiply the divisor thus increased, by the last figure of the root; subtract the product from the dividend ; to the remainder annex the next period for a new dividend. t 5. Double the whole root found for a... | |
 | Benjamin Greenleaf - 1858 - 456 σελίδες
...product Mow the trial divisor, and add it to the saute fur a true divisor. j\fullij>l// the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring domi the next period for a new dividend. To the last true divisor and the number immediate!;/ over... | |
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Multiply this complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. 
