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" ... multiply the square of the diameter by ,7854 and the product will be- the area. "
The Tutor's Assistant: Being a Compendium of Practical Arithmetic, for the ... - Σελίδα 168
των Francis Walkingame - 1833
Πλήρης προβολή - Σχετικά με αυτό το βιβλίο

The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1785 - 350 σελίδες
...1 . Multiply Half the the Circumference by Half the Diameter, and the Product will be the Area. Or, 2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area. Or, • 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or,...

A Treatise on Mensuration, Both in Theory and Practice

Charles Hutton - 1788 - 728 σελίδες
...the area CAE of the whole circle or feftor accordingly. ^_. £. D. * RULE II. « Multiply the fquare of the diameter by '7854, and the product will be the area* EXAMPLES. i, What is the area of a circle whofe diameter is I, and circumference 3'i4i6? Vl4-l6 XI...

The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1806 - 342 σελίδες
...RULES. 1. Multiply Half the Circumference by Half the Diameter, and tin- Product will 1& the Area. Or, 2. Multiply the Square of the Diameter by ,7854, and the Product will be the Area. Or, 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or, 4....

Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 σελίδες
...circumference^ and the product is the area ; or if the diameter is given without the circumference, multiply the square of the diameter by ,7854 and the product will be the area. EXAMPLE8. 1. Required the area of a circle whose diameter 'is 12 inches, and circumference 37,7 inches....

The complete measurer: or, The whole art of measuring, containing the ...

Thomas Keith - 1817 - 306 σελίδες
...' the area of a circle whose diameter is d. circumference and diameter, 'and it will give the area. 2. Multiply the square of the diameter by 7854, and the product will be the area. 3. As 452 is to 355, so is the square of the diamuter to the area. 3' "3 : 355 :: diameter I : circumference...

Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1818 - 246 σελίδες
...circumference, and the product is the area ; or if the diameter is given • •without the circumference, multiply the square of the diameter by ,7854 and the product will be- the area. EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches....

A general view of the sciences and arts, Τόμος 1

William Jillard Hort - 1822 - 308 σελίδες
...circle. Rule 1. Multiply half the circumference by half the diameter, and the product will be the area. Rule 2. Multiply the square of the diameter by 7854', and the product will be the area. ProUem. To find the area of an ellipse. Multiply the product of the two axes, by the number 7854. for...

A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1822 - 562 σελίδες
...1 5. The Diameter being given to find the Area of a Circle without finding the Circumference. RULE. Multiply the square of the diameter by -7854,* and the product will be the area of the circle, whose diameter was given. EXAMP. The diameter of a circle being 12, to find the area...

Dictionary of the Mathematical and Physical Sciences, According to the ...

James Mitchell - 1823 - 666 σελίδες
...Diameter being given. 1. Multiply the diameter by 3-14159, and the product will be the circumference. 2. Multiply the square of the diameter by -7854, and the product •will be the area. Or general, if we put diameter = D, circumference = C, area — A, and 3-141S9 = 1', we have the following...

Daboll's Schoolmaster's Assistant, Improved and Enlarged

Nathan Daboll - 1825 - 248 σελίδες
...circumference' and the product is the area; or if the diameter is ^iven vdthout the circumference, multiply the square of the diameter by ,7854 and the product will be the urea. EXAMPLES. 1. Required Hie area of a circle whose diameter is 12 inches, and circumference 37,7...




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