 | 1801 - 446 σελίδες
...in division, and- it will be the first figure of the root required. 2. Subtract the assumed square from the first period, and to the remainder bring down the next period for a dividend. ' 3. Place viz. 2oooop ; but 100000 has one place less than 1000 and 100 together have... | |
 | Samuel Webber - 1812 - 260 σελίδες
...therefore 999X99, or the product of any other two pumbers, consisting of 2. Subtract the assumed square from the first period, and to the remainder bring down the next period for a dividend. J5. Place the double of the root, already found, on the left of the dividend for a... | |
 | Daniel Staniford - 1818 - 332 σελίδες
...hand period, and place it under this period, and its root in the quotient ; subtract the square number from the first period, and to the remainder bring down the next period and call this the Resolvend. 3. Double the quotient for a divisor. 4. Find how often the divisor is contained... | |
 | Benjamin Snowden - 1835 - 108 σελίδες
...left hand period, and put its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...first term of the SECOND COLUMN. This, multiplied by the same figure, will give the first term of the THIRD COLUMN. Thus continue until the number of columns...subtract the product from the first period, and to the re. mainder bring down the next period, and it will form the FIRST DIVIDEND. Again, add this same figure... | |
 | John Darby (teacher of mathematics.) - 1843 - 236 σελίδες
...contained in the first or left hand period, and put its root for a quotient. Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. 5. Double the quotient figure, for the first portion of the divisor ; then find what... | |
 | Davis Wasgatt Clark - 1844 - 394 σελίδες
...on the right, in the place of a quotient in division. Subtract the cube of this figure of the root from the first period, and to the remainder bring down the next period, and call this number the dividend. 3. Multiply the square of the root just found by 300 for a divisor.... | |
 | William Watson (of Beverley.) - 1845 - 188 σελίδες
...placing the square under the same, and its root in the quotient. 3. — Subtract the square number from the first period, and to the remainder bring down the next two figures or period for a dividend. 4. — Double the quotient and place it for a divisor on the... | |
 | George Roberts Perkins - 1849 - 356 σελίδες
...first term of the SECOND COLUMN. This, multiplied by the same figure, will give the first term of the THIRD COLUMN. Thus continue until the number of columns...remainder bring down the next period, and it will farm the FIRST DIVIDEND. Again, add this same figure to the term of the FIRST COLUMN, multiply the... | |
 | George Roberts Perkins - 1849 - 344 σελίδες
...and place the product for the first term of a column marked 2d COL. Again, multiply this last result by the same figure, and subtract the product from the first period, and to the remainder annex the next period, and it will give the FIRST DIVIDEND. This same figure must be added to the first... | |
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Subtract this square number from the first period, and to the remainder bring down the next period for a dividend. 
