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" Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in Ibs. avoirdupois. What weight will break... "
Modern Carpentry and Building: Giving Methods of Obtaining the Various Cuts ... - Σελίδα 154
των William Allen Sylvester - 1896 - 254 σελίδες
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A concise system of mathematics

Alexander Ingram - 1830 - 120 σελίδες
...both ends ind loaded in the centre. RULE. Multiply the tabular value of S by 4 times the breadth and square of the depth in inches, and divide the product by the length in inches for the weight. NOTE 1 . When the beam \sjixed at each end, and loaded in the middle, the result...

A Treatise on the Strength, Flexure, and Stiffness of Cast Iron Beams and ...

William Turnbull - 1832 - 194 σελίδες
...times the breadth in inches by the sum of the segments of the length of bearing in feet, drawn into the square of the depth in inches, and divide the product by the rectangle of the segments, for the load to be supported in pounds. Example 5. In the equation there...

The millwright & engineer's pocket companion

William Templeton (engineer.) - 1833
...— Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in libs, avoirdupois nearly. H2 Kama of Dailies. *;. Bar. 1 third....

Engineers' and Mechanics' Pocket-book ...

Charles Haynes Haswell - 1844 - 264 σελίδες
...oath. Ends, and Loaded in the Middle. RULE. — Multiply the Value in the preceding table by six times the breadth, and the square of the depth, in inches, and divide by the length in feet. NOTE.— When the weight is laid uniformly along its length, the result must...

The Practical Model Calculator: For the Engineer, Mechanic, Machinist ...

Oliver Byrne - 1851 - 293 σελίδες
...— Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in Ibs. avoirdupois. What weight will break a beam of oak 4 inches...

Engineers' and Mechanics' Pocket-book ...

Charles Haynes Haswell - 1851 - 286 σελίδες
...both Ends, and Loaded in the Middle. RULE. — Multiply the Value in the preceding table by six times the breadth, and the square of the depth, in inches, and divide by the length in feet. NOTE.— When the weight is laid uniformly along its length, the result must...

Orr's Circle of the Sciences: Mechanical philosophy

William Somerville Orr - 1856
...carricd by a beam 1 inch broad, 1 inch deep, and 1 foot long, by the breadth in inches, and twice by the depth in inches, and divide the product by the length in feet. Example. — A beam 1 inch square and 1 foot long, carrics 5 cwt. at its end : required the load carried...

Appletons' Cyclopædia of Drawing: Designed as a Text-book for the Mechanic ...

William Ezra Worthen - 1857 - 410 σελίδες
...centre : Rule — Multiply the constant S, for the material from the above table, by the breadth and square of the depth in inches, and divide the product by the length in feet. Example. — What is the ultimate strength of a beam of white pine, 20 feet long, 8 inches wide, and...

APPLETONS' CYCLOPAEDIA OF DRAWING

W.E. WORTHEN - 1857
...centre : Rule — Multiply the constant S, for the material from the above table, by the breadth and square of the depth in inches, and divide the product by the length in feet. Example. — What is the ultimate strength of a beam of white pine, 20 feet long, 8 inches wide, and...

The Practical Model Calculator, for the Engineer, Mechanic, Machinist ...

Oliver Byrne - 1863 - 588 σελίδες
...— Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in Ibs. avoirdupois. What weight will break a beam of oak 4 inches...




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