A System of Arithmetic: Reprinted from the Mathematical Text-bookPublished and sold by William Hilliard, 1812 - 248 σελίδες |
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Σελίδα 32
... cyphers , which would happen in the common way , as may be seen by working an example at large . * This follows from the second contraction in multiplication , EXAMPLES . 1. Divide 31046835 by 56 = 7x8 . 32 SIMPLE DIVISION .
... cyphers , which would happen in the common way , as may be seen by working an example at large . * This follows from the second contraction in multiplication , EXAMPLES . 1. Divide 31046835 by 56 = 7x8 . 32 SIMPLE DIVISION .
Σελίδα 39
... and November , have each 30 days ; each of the other months has 31 , except Feb- ruary , which has 28 in common years , and 29 in leap years . hours , or w . | Julian year CIRCULAR MOTION . 60 seconds make 1 minute , marked REDUCTION . 39.
... and November , have each 30 days ; each of the other months has 31 , except Feb- ruary , which has 28 in common years , and 29 in leap years . hours , or w . | Julian year CIRCULAR MOTION . 60 seconds make 1 minute , marked REDUCTION . 39.
Σελίδα 40
... common use are liable to great uncertainty and inconvenience . There being no fixed standard at hand , by which their accuracy can be tested , a great variety of measures , bearing the same name , has ob- tained in different countries ...
... common use are liable to great uncertainty and inconvenience . There being no fixed standard at hand , by which their accuracy can be tested , a great variety of measures , bearing the same name , has ob- tained in different countries ...
Σελίδα 44
... common and 6 in leap years was considered as belonging to no month . Each month was divid- ed into three parts , called decades . The day was divided into 10 hours , each hour into 100 minutes , and each minute into 100 seconds . This ...
... common and 6 in leap years was considered as belonging to no month . Each month was divid- ed into three parts , called decades . The day was divided into 10 hours , each hour into 100 minutes , and each minute into 100 seconds . This ...
Σελίδα 62
... common meas- ure required . 2. When there are more than two numbers , find the greatest common measure of two of them as before ; and of that common measure and one of the other numbers ; then will the greatest common measure , last ...
... common meas- ure required . 2. When there are more than two numbers , find the greatest common measure of two of them as before ; and of that common measure and one of the other numbers ; then will the greatest common measure , last ...
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A System of Arithmetic: Reprinted From the Mathematical Text-Book (Classic ... Samuel Webber Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
A System of Arithmetic: Reprinted from the Mathematical Text-Book Samuel Webber Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
2qrs 3qrs amount of 11 annuity annum answer required arithmetical Arithmetical Progression barrel bushel called carats cent common difference compound fraction compound interest contain couplets cube root cyphers debt decimal DEMONSTRATION discount Divide dividend division divisor dollar equal equated equivalent evident EXAMPLES farthings fourth gain or loss gallon geometrical geometrical progression geometrical series given number gold greater greatest common measure gross improper fraction inches last term least common multiple less number manner method of proof mixed number months multiplicand Multiply number of combinations number of places number of terms number of things payment pound present worth proportion quantities question quotient quotient figure ratio Reduce remainder repetend Rule of Three shillings Signifies simple interest square root subtract supposition taken tare tion trett TROY WEIGHT vulgar fraction weight whole number yards year's interest
Δημοφιλή αποσπάσματα
Σελίδα 129 - A wall, to be built to the height of 27 feet, was raised to the height of 9 ft. by 12 men in 6 days; how many men must be employed to finish the wall in 4 days at the same rate of working ? Ans. 36 men.
Σελίδα 210 - Find the present worth of each year by itself, discounting from the time it falls due, and the sum of all these present worths will be the present worth required.
Σελίδα 37 - Pound /6 28 Pounds 1 Quarter qr 4 Quarters 1 Hundred weight cwt 20 Hundred weight 1 Ton...
Σελίδα 193 - RULE.—Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time.* • , EXAMPLES.
Σελίδα 229 - RULE. 1. Find all the different forms of combination of all the given things, taken as many at a time, as in the question^ by problem 5, 2.
Σελίδα 229 - ... 1. Place the things so that the greatest indices may be first, and the rest in order. 2. Begin with the first letter and join it to the second, third, fourth, &c. to the last.
Σελίδα 237 - What difference is there between the interest of 500Z. at 5 per cent, for 12 years, and the discount of the same sum at the same rate, and for the same time ? Ans.
Σελίδα 172 - The difference of the extremes divided by the number of the terms less 1, gives the common difference; consequently, the same divided by the common difference must give the number of terms less 1 : hence, this quotient augmented by 1, must give the number of terms.
Σελίδα 56 - Begin at the left hand, and divide each denomination by the divisor, setting down the quotients under their respective dividends. But if there be a remainder after dividing any of the denominations except the least, find how many of the next lower denomination it is equal to, and add it to the number, if any, which was in this denomination before, then divide the sum as usual, and so on, till the whole is finished.
Σελίδα 183 - Ans. 59048. 4. What debt may be discharged in a year, or twelve months, by paying $1 the first month, $2 the second month...