Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive System of Practical Arithmetic, Adapted to the Use of Schools in the United States...J. Bolles, 1849 - 249 σελίδες |
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Σελίδα 3
... contain more of the old currency or Sterling Money , than is necessary at the present day . Another objection to those of long standing is , a deficiency of proper illustrations of the rules and examples . To remedy these defects , a ...
... contain more of the old currency or Sterling Money , than is necessary at the present day . Another objection to those of long standing is , a deficiency of proper illustrations of the rules and examples . To remedy these defects , a ...
Σελίδα 6
... contain , 240 To find the tonage of a ship , To guage a cask , Of mechanical powers , To measure loads of wood , A practical system of Book - keeping , 241 241 242 243 244 ARITHMETICAL TABLES . ADDITION TABLE 2 and 1 are 3 3 . TABLE OF ...
... contain , 240 To find the tonage of a ship , To guage a cask , Of mechanical powers , To measure loads of wood , A practical system of Book - keeping , 241 241 242 243 244 ARITHMETICAL TABLES . ADDITION TABLE 2 and 1 are 3 3 . TABLE OF ...
Σελίδα 23
... contain ? Ans . 720 acres . 2. General Washington was born in the year 1732 , and lived to be 67 years of age ; in what year did he die ? Ans . 1799 . 3. What number of dollars are in six parcels , each con- taining 25479 dollars ? Ans ...
... contain ? Ans . 720 acres . 2. General Washington was born in the year 1732 , and lived to be 67 years of age ; in what year did he die ? Ans . 1799 . 3. What number of dollars are in six parcels , each con- taining 25479 dollars ? Ans ...
Σελίδα 33
... contain ? In the first row 23 trees second 23 third 23 fifth fourth 23 23 In the whole 115 trees Multiplicand 23 ... contained in 1 row , and as 5 rows will con- tain 5 times as many , we may place the 5 underneath for a mul- tiplier ...
... contain ? In the first row 23 trees second 23 third 23 fifth fourth 23 23 In the whole 115 trees Multiplicand 23 ... contained in 1 row , and as 5 rows will con- tain 5 times as many , we may place the 5 underneath for a mul- tiplier ...
Σελίδα 34
... contain 3 times 365 days . Operation . We write down the multiplicand and 365 multiplicand place the multiplier under it , making 3 multiplier the greater number the multiplicand ; the less the multiplier . 1095 Product We then say 3 ...
... contain 3 times 365 days . Operation . We write down the multiplicand and 365 multiplicand place the multiplier under it , making 3 multiplier the greater number the multiplicand ; the less the multiplier . 1095 Product We then say 3 ...
Άλλες εκδόσεις - Προβολή όλων
Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ... Nathan Daboll Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ... Nathan Daboll Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2017 |
Συχνά εμφανιζόμενοι όροι και φράσεις
2qrs 3qrs acres annex annuity answer Arithmetic barrels broadcloth bushels called cent per annum ciphers common denominator common difference common multiple compound interest contained cords cost cube root cubic diameter divi dividend divisor dollars dols equal EXAMPLES farthings Federal money find the amount Find the value frustrum gain gallons given number given sum greatest common divisor hogshead hundred improper fraction inches last term least common multiple leave length lowest terms merchant bought miles mills mixed number months multiplicand Multiply Note number of terms payment pence pint pound present worth principal PROB proportion quantity quarts quotient figure rate per cent ratio Reduce remainder right hand roods Rule of Three separatrix shillings simple sold solid contents square rods square root subtract subtrahend sugar tare tens thousand units VULGAR FRACTIONS weight whole number wine yards of cloth
Δημοφιλή αποσπάσματα
Σελίδα 207 - Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms.
Σελίδα 191 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Σελίδα 195 - Find the first figure of the root by trial, and subtract its power from the left hand period of the given number. 3. To the remainder bring down the first figure in the next period, and call it the dividend. 4. Involve the root to the next inferior power to that which is given, and multiply it by the number denoting the given power, for a divisor.
Σελίδα 167 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator; and they will form the fraction required.
Σελίδα 183 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained...
Σελίδα 106 - Let the farthings in the given pence and farthings possess the second and third places ; observing to increase the second place or place of hundredths, by 6 if the shillings be odd ; and the third place by 1 "when the farthings exceed 12, and by 2 when they exceed 36. EXAMPLES. 1. Find the decimal of 7s. 9fd. by inspection. ,3 =4 6s. 5 for the odd shillings. 39=the farthings in 9|d. 2 for the excess of 36. £. ,391=dechnal required'.
Σελίδα 141 - Compute the interest to the time of the first payment ; if that be one year or more from the time the interest commenced , add it to the principal, and deduct the payment from the sum total. If there be after payments made, compute the interest on the balance due, to the next payment, and then deduct the payment as above ; and in like manner from one payment to another till all the payments are absorbed ; provided the time between one payment and another be one year or more.
Σελίδα 44 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.
Σελίδα 228 - What difference is there between the interest of 500Z. at 5 per cent, for 12 j'ears, and the discount of the same sum at the same rate, and for the same time ? Ans.
Σελίδα 119 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.