# Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous Practical Problems

Ivison, Phinney, Blakeman & Company, 1865 - 444 уелЯдет
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### Ресйечьменб

 BOOK IV 111 BOOK V 130 Practical Problems 142 BOOK VI 152 BOOK VII 172 Practical Problems 229 Miscellaneous Propositions in Plane Geometry 238 PART I 244
 Logarithms 278 RightAngled Trigonometry 288 Practical Problems 295 Practical Problems 305 SECTION II 330 SECTION III 337 Napiers Analogies 348 Practical Problems 356

### ДзмпцйлЮ брпурЬумбфб

УелЯдб 320 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
УелЯдб 28 - Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
УелЯдб 121 - In a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle ; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF.
УелЯдб 56 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
УелЯдб 27 - If one side of a triangle is produced, the exterior angle is equal to the sum of the two interior and opposite, angles; and the three interior angles of every triangle are equal to two right angles.
УелЯдб 39 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
УелЯдб 94 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
УелЯдб 63 - In a series of equal ratios, any antecedent is to its consequent, as the sum of all the antecedents is to the sum of all the consequents. Let a: 6 = c: d = e :/. Then, by Art.
УелЯдб 75 - FGL ; (vi. 6.) and therefore similar to it ; (vi. 4.) wherefore the angle ABE is equal to the angle FGL: and, because the polygons are similar, the whole angle ABC is equal to the whole angle FGH ; (vi.
УелЯдб 111 - From a given point, to draw a line parallel to a given line. Let A be the given point, and BC the given line.