 | John Dougall - 1810 - 554 σελίδες
...the solidity of the globe must be the product of ifs surface multiplied by one third of the radius. The surface of a sphere is equal to the product of the circumference of a great circle on its being multiplied by the diameter. Let ALD represent a sphere,... | |
 | 1835 - 684 σελίδες
...revolution, whether m surface or in content, is less than that of the two figures (14.). PROP. 16. The surface of a sphere is equal to the product of the circumference and diameter of the generating circle. For if this product be not equal to the surface... | |
 | Anna Cabot Lowell - 1846 - 216 σελίδες
...x4 square J.OU IUU feet = 12£f square feet; and the solidity is 12£t X 2f = 33$£ cubic feet. 3O8. The surface of a sphere is equal to the product of the circumference of a great circle multiplied by the diameter ; and the product of this surface multiplied... | |
 | Joseph Bateman - 1852 - 376 σελίδες
...sphere ; multiply it by two-thirds of the height ; the product is the content. ways by the surface. The surface of a sphere is equal to the product of the cireumference and diamcter of the generating cirele ; that i.*, to four timcs the area of one of its... | |
 | Charles Davies, William Guy Peck - 1855 - 592 σελίδες
...containing many individ- anj voiunic generated by revolving a regular semi-polygon about its diameter. The surface of a sphere is equal to the product of...the diameter by the circumference of a great circle ; or it is equivalent to the area of four great circles. Denoting the radius of the sphere by r, and... | |
 | Charles Davies, William Guy Peck - 1855 - 628 σελίδες
...SURFACE. A subdivision of an order of surface. Surfaces are classed. semi-polygon about i's diameter. The surface of a sphere is equal to the product of the diameter by the circumference like lines, into algebraic and transccmUnlal. 'of a great circle ; or it is equivalent to the The algebraic... | |
 | Benjamin Greenleaf - 1862 - 532 σελίδες
...semi-cinmmfercnce ABCDEF, and the perpendicular OI will be equal to tho radius OA ; hence, the surface of tho sphere is equal to the product of the diameter by the circumference of a great circle. B 589. Cor. 1. The surface of a sphere //\ is equal to the area of four of its great circles. For the... | |
 | Benjamin Greenleaf - 1862 - 518 σελίδες
...semi-circumference ABCDEF, and the perpendicular 0 1 will be equal to the radius 0 A ; hence, the surface of the sphere is equal to the product of the diameter by the circumference of a great circle. 589. Cor. 1. The surface of a sphere is equal to the area of four of its great circles. For the area... | |
 | Benjamin Greenleaf - 1863 - 504 σελίδες
...semi-circumference ABCDEF, and the perpendicular 0 I will be equal to the radius 0 A ; hence, the surface of the sphere is equal to the product of the diameter by the circumference of a great circle. 589. Cor. 1. The surface of a sphere is equal to the area of four of its great circles. For the area... | |
 | Benjamin Greenleaf - 1868 - 340 σελίδες
...semi-circumference ABCDEF, and the perpendicular 0 I will be equal to the radius 0 A ; hence, the surface of the sphere is equal to the product of the diameter by the circumference of a great circle. 589. Cor. 1. The surface of a sphere is equal to the area of four of its great circles. For the area... | |
| |
The area of the surface of a sphere is equal to the area of the... 
