 | Wardhaugh Thompson - 1771 - 324 σελίδες
...from Multiplication of Vulgar 1 ractions, the reafon why (in Multiplication of Decimals) we muft have as many Decimal places in the product as there are in both the Multiplicand and Multiplier. FIRST then according to Multiplication of Vulgar Fractions, let us... | |
 | Charles Davies - 1838 - 292 σελίδες
...places ,296=^. in the two factors. 2. Multiply ,3 by ,02. OPERATION. ,3 x ,02 =^ x ^=T^=,006 answer. To express the 6 thousandths decimally we have to...decimal places in the product as there are in both multi plicand and multiplier. Therefore, to multiply one decimal by another, we have the following... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...91.6264232009 by 0.0172021234. DIVISION OF DECIMALS. -10. In multiplication we have seen that there are as many decimal places in the product as there are in both the factors; and since division is the reverse of multiplication, it follows that the number of decimal... | |
 | Charles DAVIES (LL.D.) - 1843 - 348 σελίδες
...decimal places in the two factors. 2. Multiply ,3 by ,02. OPERATION. ^x,02=T3lyx1%2o=T^oo=,006 answer. To express the 6 thousandths decimally we have to...multiplier. Therefore, to multiply one decimal by another, we have the following RULE. Multiply as in simple numbers, andpoint off in the product, from the right... | |
 | Charles Davies - 1844 - 358 σελίδες
...number of decimal places in the two factors. 2. Multiply ,3 by ,02. OPERATION. ==,006 answer,296=^ To express the 6 thousandths decimally we have to...multiplier. Therefore, to multiply one decimal by another, we have the following RU1E. Multiply asin simple numbers, andpoint off in the product, from the right... | |
 | James Morrison (accountant.) - 1845 - 324 σελίδες
...necessary to be pointed off? A. I prefix ciphers to make up the deficiency. (3.) Q. Why do you point off as many decimal places in the PRODUCT, as there are in both factors ? A. The reason is, that the operation here is the same as in Multiplication of Vulgar Fractions... | |
 | Charles Davies - 1846 - 362 σελίδες
...places in the two factors. OPERATION. ,296=^ 2. Multiply ,3 by ,02. OPERATION. x02=x02==5006 answer. To express the 6 thousandths decimally we have to prefix two ciphers to the 6, and this makes as manydecimal places in the product as there are in both multiplicand and multiplier. Therefore, to multiply... | |
 | George Roberts Perkins - 1846 - 266 σελίδες
...product as there are in both the factors. We therefore have this «RULE. <w in whole numbers, and give as many decimal places in the product, as there are in both the factors taken together. When there are not as many places in the product, prefix ciphers. • .... | |
 | Charles Davies - 1847 - 368 σελίδες
...true "" ' for any two factors whatever. 2. Multiply .3 by .02. OPERATION. .3 x .02=T315 xj^ — Y/O~B =-006 answer. Now, to express the 6 thousandths decimally,...as in simple numbers, and point off in the product, from the right hand, as many figures for decimals as are equal to the number of decimal places in the... | |
 | Charles Davies - 1847 - 368 σελίδες
...true for any two factors whatever. 2. Multiply .3 by .02. OPERATION. .3 x .02=T% xT%2o ^'ny^o-.00e answer. Now, to express the 6 thousandths decimally,...another, Multiply as in simple numbers, and point of in the product, from the right hand, as many figures for decimals as are equal to the number of... | |
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Now, to express the 6 thousandths decimally, we have to prefix two ciphers to the 6, and this makes as many decimal places in the product as there are in both multiplicand and multiplier. 
