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" Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE.—(') Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought. "
A Key to the Western Calculator: Containing the Solution of All the Examples ... - Σελίδα 94
των John Armstrong - 1831 - 139 σελίδες
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The American Arithmetic: Adapted to the Currency of the United States ...

Oliver Welch - 1812 - 236 σελίδες
...area of a circle whose circumference is 44 rods ? 44X 44 X -07958= 1 54-06688, Ans. >» PROBLEM VI. The area of a circle given to find the diameter. RULE. Divide the area by 0-7854 and extract the square root of the guotent ; the root is the diameter sought. (See application...

A New and Concise System of Arithmetick: Containing Vulgar, Decimal, and ...

Beriah Stevens - 1822 - 436 σελίδες
...the area of a circle whose circumference is 44 1 44 X44 X ,07958, = 1 54,06608, answer. PROBLEM 16lh. The area of a circle given, to find the diameter. RULE. Divide the area by ,7854 and extract the equare root of the quotient ; the root ivill be the diameter sought....

A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829 - 246 σελίδες
...the area of a circle whose circumference is 30 rods? 30 x30x, 07958=7 1,62200 rods. Ans. PROBLEM 1V. The area of a circle given to find the diameter. RULE. — Divide the area by ,7854 — and the square root ef the quotient is the required diameter. EXAMPLES. 1. Required...

A Complete System of Mensuration of Superficies and Solids, of All Regular ...

Tobias Ostrander - 1834 - 182 σελίδες
...diar meter is 6 rods, at the rate of 8 cents per square foot ? Ans. 615,816432 dollars. PROBLEM IV. The area of a circle given, to find the diameter. Rule — Divide the area by the decimal ,7854, and extract the square root of the quotient. EXAMPLES. 1. The area of a...

Welch's Improved American Arithmetic: Adapted to the Currency of the United ...

1841 - 200 σελίδες
...What is the area of a circle whose circumference IB 44 rods? 44X44X-07953=154-0668S., Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE. — (!). Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought. (See application...




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