 | A. Melrose (Teacher) - 1795 - 140 σελίδες
...divifor, thus increafed, by the laft. figure placed iu the root : Subtract the produft from the drwdend, and to the remainder annex the next period for a new dividend ; with which proceed in the fame manner, and'fo on,. till all the periods are ufed. I Required the... | |
 | John Davidson, Robert Scott (writing master) - 1818 - 190 σελίδες
...also on the right of the divisor ; multiply the divisor thus completed ly this nea figure, suUnii.t the product from the dividend, and to the remainder annex the next fart for a new dividend. To the complete divisor add the last figure of the reot, the turn will be... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 σελίδες
...both in the root and on the right of the Disisor; also by it multiply the Divisor thus completed, and subtract the Product from the Dividend, and to the...Remainder annex the next period for a new Dividend. To the completed Divisor add the figure last put in the root ; the sum is a new Divisor, with which proceed... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 σελίδες
...together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under the complete... | |
 | 1843 - 142 σελίδες
...product write also the square of the trial-figure, then multiply the sum of these by the trial-figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. EVOLUTION.ciphers for a new divisor, with which find anolner trialfigure, and proceed as before. 1.... | |
 | George Roberts Perkins - 1846 - 266 σελίδες
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figurt of the root, and subtract the product from the dividend, and to the remainder annex the next period, for a SECOND DIVIDEND. IV. To the last TRUE DIVISOR, add the last figure of the not, for a new TRIAL DIVISOR,... | |
 | James W. Kavanagh - 1846 - 304 σελίδες
...quotient figure, and enter the product under the dividend ; subtract this product from the dividend above, and to the remainder annex the next period for a new dividend. But should it so happen that the divisor is not contained in the dividend, then enter 0 in the quotient,... | |
 | George Roberts Perkins - 1849 - 346 σελίδες
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the...remainder annex the next period, for a NEW DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of the root ; the sum, with a cipher annexed, will... | |
 | George Roberts Perkins - 1849 - 344 σελίδες
...last term of the 2d column. Again, multiply this last result by this second figure of the root, and subtract the product from the dividend, and to the...remainder annex the next period for a NEW DIVIDEND. Proceed with this second figure of the root precisely as was done with the first figure, and so continue,... | |
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... subtract the product from the dividend, and to the remainder annex the next period for the next dividend. 
