Books 3-9The University Press, 1908 |
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Αποτελέσματα 1 - 5 από τα 37.
Σελίδα 28
... double negative , οὐκ ἄρα ἡ εὐθεῖα ... OVK EXEúσeral , literally " the straight line ... will not not - pass .... " " " Heron says on III . II : “ Euclid in proposition 11 has supposed the two circles to touch internally , made his ...
... double negative , οὐκ ἄρα ἡ εὐθεῖα ... OVK EXEúσeral , literally " the straight line ... will not not - pass .... " " " Heron says on III . II : “ Euclid in proposition 11 has supposed the two circles to touch internally , made his ...
Σελίδα 34
... double contact is possible ) ; but he devotes some space to proving that the centre of the " outer " circle must lie within the " inner " circle , a fact which he represents Euclid as asserting ( " sicut dixit Euclides " ) , though ...
... double contact is possible ) ; but he devotes some space to proving that the centre of the " outer " circle must lie within the " inner " circle , a fact which he represents Euclid as asserting ( " sicut dixit Euclides " ) , though ...
Σελίδα 35
... double of AF . For the same reason [ III . 3 ] CD is also double of CG ; and AB is equal to CD ; therefore AF is also equal to CG . And , since AE is equal to EC , B the square on AE is also equal to the square on EC . But the squares ...
... double of AF . For the same reason [ III . 3 ] CD is also double of CG ; and AB is equal to CD ; therefore AF is also equal to CG . And , since AE is equal to EC , B the square on AE is also equal to the square on EC . But the squares ...
Σελίδα 36
... double of AF , and CD double of CG ; therefore AB is equal to CD . Therefore etc. Q. E. D. Heron ( an - Nairizi , pp . 125-7 ) has an elaborate addition to this proposition in which he proves , first by reductio ad absurdum , and then ...
... double of AF , and CD double of CG ; therefore AB is equal to CD . Therefore etc. Q. E. D. Heron ( an - Nairizi , pp . 125-7 ) has an elaborate addition to this proposition in which he proves , first by reductio ad absurdum , and then ...
Σελίδα 46
... double of 10 the angle BAC . 15 For let AE be joined and drawn through to F. Then , since EA is equal to EB , the angle EAB is also equal to the angle EBA ; A E F G [ 1.5 ] therefore the angles EAB , EBA are double of the angle EAB ...
... double of 10 the angle BAC . 15 For let AE be joined and drawn through to F. Then , since EA is equal to EB , the angle EAB is also equal to the angle EBA ; A E F G [ 1.5 ] therefore the angles EAB , EBA are double of the angle EAB ...
Συχνά εμφανιζόμενοι όροι και φράσεις
ABCD angle ABC angle BAC antecedent Aristotle base bisected centre circle ABC circumference construction continued proportion corresponding sides cube number definition diameter drawn enunciation equal angles equiangular equimultiples Euclid Eutocius ex aequali four magnitudes geometrical geometrical progression given circle given straight line greater ratio greatest common measure Heiberg hypothesis Iamblichus joined less mean proportional numbers measures the number multiple multitude Nicomachus odd number parallel parallelogram pentagon polygon Porism prime number Proclus Prop proper fraction proposition PROPOSITION 13 proved rect rectangle rectangle contained rectilineal figure reductio ad absurdum remaining angle right angles segment semicircle similar and similarly similar plane numbers Simson solid numbers square number subtracted taken Theon Theon of Smyrna theorem touches the circle triangle ABC unit VIII δὲ καὶ πρὸς τὸ τοῦ
Δημοφιλή αποσπάσματα
Σελίδα 34 - EQUAL straight lines in a circle are equally distant from the centre ; and those which are equally distant from the centre, are equal to one another.
Σελίδα 65 - If a straight line touch a circle, and from the point of contact a chord be drawn, the angles which this chord makes with the tangent are equal to the angles in the alternate segments.
Σελίδα 37 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Σελίδα 234 - Prove that similar triangles are to one another in the duplicate ratio of their homologous sides.
Σελίδα 64 - From this it is manifest that if one angle of a triangle be equal to the other two it is a right angle, because the angle adjacent to it is equal to the same two ; (i.
Σελίδα 209 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.
Σελίδα 90 - EF at right angles (9. 1.) to AB, AC ; DF, EF produced meet one another : for, if they do not meet, they are parallel, wherefore AB, AC, which are at right angles to them, are parallel ; which is absurd : let them meet in F, and join FA ; also, if the point F be not in BC, join BF, CF : then, because AD is equal to DB, and DF common, and at right angles to AB, the base AF is equal (4.
Σελίδα 80 - In a given circle to place a straight line, equal to a given straight line which is not greater than the diameter of the circle. Let ABC be the given circle, and D the given straight line, not greater than the diameter of the circle.
Σελίδα 212 - ... be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA, as CE to EA. Join BE, CD ; Then the triangle BDE is equal to the triangle CDE*, * «.i.
Σελίδα 95 - In the same manner, it may be demonstrated that the straight lines EC, ED, are each of them equal to EA or EB ; therefore the four straight lines EA, EB, EC, ED, are equal to one another ; and the circle described from the centre E, at the distance of one of them, shall pass through the extremities of the other three, and be described about the square ABCD.