A Treatise of Practical Surveying: Which is Demonstrated from Its First Principles ... |
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Σελίδα 154
PROBLEM III . To take a survey by the chain only , when all the angles cannot be
seen from one point within . Plate VI . fig . 7 . 1 Let the ground to be surveyed be
represented by 1 , 2 , 3 , 4 , & c . Since all the angles cannot be seen from one ...
PROBLEM III . To take a survey by the chain only , when all the angles cannot be
seen from one point within . Plate VI . fig . 7 . 1 Let the ground to be surveyed be
represented by 1 , 2 , 3 , 4 , & c . Since all the angles cannot be seen from one ...
Σελίδα 183
The first part is plain , from considering that a piece of ground in a square form ,
whose side is a perch , must contain a perch of ground ; and that 40 such
perches make a rood , or stang , and four roods an acre ; or which is the same
thing , that ...
The first part is plain , from considering that a piece of ground in a square form ,
whose side is a perch , must contain a perch of ground ; and that 40 such
perches make a rood , or stang , and four roods an acre ; or which is the same
thing , that ...
Σελίδα 186
To find the content of an oblong piece of ground . Multiply the length by the
breadth , for the content . EXAMPLE . Plate I. fig . S. Let ABCD be an oblong
piece of ground , whose length AB is 14C . 25L . and breadth 8C . 37L . I demand
the ...
To find the content of an oblong piece of ground . Multiply the length by the
breadth , for the content . EXAMPLE . Plate I. fig . S. Let ABCD be an oblong
piece of ground , whose length AB is 14C . 25L . and breadth 8C . 37L . I demand
the ...
Σελίδα 193
The content of a triangular piece of ground , and the base given , to find the
perpendicular . Divide the content in perches , by half the base in perches ; and
the quotient will give you the perpendicular , in perches and so in chains .
EXAMPLES ...
The content of a triangular piece of ground , and the base given , to find the
perpendicular . Divide the content in perches , by half the base in perches ; and
the quotient will give you the perpendicular , in perches and so in chains .
EXAMPLES ...
Σελίδα 208
To determine the area of a piece of ground , having the map given , by reducing it
to one triangle equal thereto , and thence finding its content . Plate VIII . fig . 5 .
Let ABCDEFGH be a map of ground , which you would reduce to one triangle ...
To determine the area of a piece of ground , having the map given , by reducing it
to one triangle equal thereto , and thence finding its content . Plate VIII . fig . 5 .
Let ABCDEFGH be a map of ground , which you would reduce to one triangle ...
Τι λένε οι χρήστες - Σύνταξη κριτικής
Δεν εντοπίσαμε κριτικές στις συνήθεις τοποθεσίες.
Συχνά εμφανιζόμενοι όροι και φράσεις
acres angle Answer base bearing called centre chains chord circle Co-sec Co-sine Co-tang column contained decimal difference direct distance divided division draw drawn east edge equal EXAMPLE feet field field-book figures four four-pole fourth give given greater ground half height Hence inches laid land Lat Dep length less logarithm manner measure method multiplied needle object observe opposite parallel perches perpendicular plain plane Plate pole prob PROBLEM proportion quantity quotient radius reduce remainder right angles right line root scale Secant sect side sights sine square station suppose survey taken Tang tangent theo THEOREM third triangle triangle ABC true turn variation whence whole
Δημοφιλή αποσπάσματα
Σελίδα 25 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Σελίδα 207 - ... that triangles on the same base and between the same parallels are equal...
Σελίδα 40 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Σελίδα 43 - Triangles upon equal bases, and between the same parallels, are equal to one another.
Σελίδα 103 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Σελίδα 31 - Figures which consist of more than four sides are called polygons ; if the sides are all equal to each other, they are called regular polygons. They sometimes are named from the number of. their sides, as a five-sided figure is called a pentagon, one of six sides a hexagon, &"c.
Σελίδα 31 - ... they are called regular polygons. They sometimes are named from the number of their sides, as a five-sided figure is called a pentagon, one of. six sides a hexagon, &c. but if their sides are not equal to each other, then they are called irregular polygons, as an irregular pentagon, hexagon, &c.
Σελίδα 45 - The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other; the square root of the difference of the squares of the hypothenuse and given side will be the required side.
Σελίδα 265 - As the length of the whole line, Is to 57.3 Degrees,* So is the said distance, To the difference of Variation required. EXAMPLE. Suppose it be required to run a line which some years ago bore N. 45°.
Σελίδα 32 - Things that are equal to one and the same thing are equal to one another." " If equals be added to equals, the wholes are equal." " If equals be taken from equals, the remainders are equal.
Πληροφορίες βιβλιογραφίας
| Τίτλος | A Treatise of Practical Surveying: Which is Demonstrated from Its First Principles ... |
| Συγγραφέας | Robert Gibson |
| Έκδοση | 3 |
| Εκδότης | Lewis Nichols, 1806 |
| Πρωτότυπο από | το Πανεπιστήμιο του Μίτσιγκαν |
| Ψηφιοποιήθηκε στις | 26 Μάιος 2007 |
| Μέγεθος | 452 σελίδες |
| Εξαγωγή αναφοράς | BiBTeX EndNote RefMan |