A Treatise of Practical Surveying: Which is Demonstrated from Its First Principles ... |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 5.
Σελίδα 42
... lines AB , CD , so as to make the alternate angles AEF , EFD equal to each
other , then the lines AB and CD will be parallel . Fig . 22 . If it be denied that AB
is parallel to CD , let IK be parallel to it ; then IEF = ( EFD ) = AEF ( by part 2. theo .
3. ) ...
... lines AB , CD , so as to make the alternate angles AEF , EFD equal to each
other , then the lines AB and CD will be parallel . Fig . 22 . If it be denied that AB
is parallel to CD , let IK be parallel to it ; then IEF = ( EFD ) = AEF ( by part 2. theo .
3. ) ...
Σελίδα 59
For MN and mn being equal and parallel , FN will be parallel to EN ; and in the
same manner , GO to FN ( by theo . 12 ) therefore AM , MN , NO , being all equal
by construction , it is plain ( from theo . 20 ) that AÉ , EF , FG , & c . will likewise be
...
For MN and mn being equal and parallel , FN will be parallel to EN ; and in the
same manner , GO to FN ( by theo . 12 ) therefore AM , MN , NO , being all equal
by construction , it is plain ( from theo . 20 ) that AÉ , EF , FG , & c . will likewise be
...
Σελίδα 63
Draw the diagonal AC , and parallel to it ( by prob . 8. ) DE , meeting AB produced
in E ; then draw CE , and ECB will be the triangle required . For the triangles ADC
, AEC being upon the same base AC , and under the same parallel ED ( by ...
Draw the diagonal AC , and parallel to it ( by prob . 8. ) DE , meeting AB produced
in E ; then draw CE , and ECB will be the triangle required . For the triangles ADC
, AEC being upon the same base AC , and under the same parallel ED ( by ...
Σελίδα 103
through B draw BD parallel to AC , and make HF = DC , and join BF ; take BI = BA
, and draw IG parallel to BD or AC . It is then plain that AH will be the sum , and HI
the difference of the sides AB and BC ; and since HB = BC , and BE perp and ...
through B draw BD parallel to AC , and make HF = DC , and join BF ; take BI = BA
, and draw IG parallel to BD or AC . It is then plain that AH will be the sum , and HI
the difference of the sides AB and BC ; and since HB = BC , and BE perp and ...
Σελίδα 199
Let AH be perpendicular to AB and equal to AC and HE , FCG , parallel to AB ;
then making AH ( = AC ) radius , AF ( = CD ) will be the sine of CAD , and the
parallelograms ABEH ( the product of the given sides ) and ABGF the double
area of ...
Let AH be perpendicular to AB and equal to AC and HE , FCG , parallel to AB ;
then making AH ( = AC ) radius , AF ( = CD ) will be the sine of CAD , and the
parallelograms ABEH ( the product of the given sides ) and ABGF the double
area of ...
Τι λένε οι χρήστες - Σύνταξη κριτικής
Δεν εντοπίσαμε κριτικές στις συνήθεις τοποθεσίες.
Συχνά εμφανιζόμενοι όροι και φράσεις
acres angle Answer base bearing called centre chains chord circle Co-sec Co-sine Co-tang column contained decimal difference direct distance divided division draw drawn east edge equal EXAMPLE feet field field-book figures four four-pole fourth give given greater ground half height Hence inches laid land Lat Dep length less logarithm manner measure method multiplied needle object observe opposite parallel perches perpendicular plain plane Plate pole prob PROBLEM proportion quantity quotient radius reduce remainder right angles right line root scale Secant sect side sights sine square station suppose survey taken Tang tangent theo THEOREM third triangle triangle ABC true turn variation whence whole
Δημοφιλή αποσπάσματα
Σελίδα 25 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Σελίδα 207 - ... that triangles on the same base and between the same parallels are equal...
Σελίδα 40 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Σελίδα 43 - Triangles upon equal bases, and between the same parallels, are equal to one another.
Σελίδα 103 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Σελίδα 31 - Figures which consist of more than four sides are called polygons ; if the sides are all equal to each other, they are called regular polygons. They sometimes are named from the number of. their sides, as a five-sided figure is called a pentagon, one of six sides a hexagon, &"c.
Σελίδα 31 - ... they are called regular polygons. They sometimes are named from the number of their sides, as a five-sided figure is called a pentagon, one of. six sides a hexagon, &c. but if their sides are not equal to each other, then they are called irregular polygons, as an irregular pentagon, hexagon, &c.
Σελίδα 45 - The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other; the square root of the difference of the squares of the hypothenuse and given side will be the required side.
Σελίδα 265 - As the length of the whole line, Is to 57.3 Degrees,* So is the said distance, To the difference of Variation required. EXAMPLE. Suppose it be required to run a line which some years ago bore N. 45°.
Σελίδα 32 - Things that are equal to one and the same thing are equal to one another." " If equals be added to equals, the wholes are equal." " If equals be taken from equals, the remainders are equal.