 Theorem. The greater side of every triangle is opposite to the greater angle. Let ABC be a triangle of which the side AC is greater than the side AB ; the angle ABC is also greater than the angle BCA. Because AC is greater than AB, make...  Elements of geometry and mensuration - Σελίδα 22των Thomas Lund - 1854 - 192 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Robert Simson - 1762 - 488 σελίδες
...therefort any two angles, &c. Q^ED PROP. XVIII. THEOR. HE greater fide of every triangle is oppofite to the greater angle. Let ABC be a triangle of which the fide AC is greater than the fide AB; the angle ABC is alfo greater than the angle BCA. Becanfe AC is... | |
 | Robert Simson - 1775 - 534 σελίδες
...Therefore any two angles, &c. Q^ED PROP. XVIII. THEO R. 'TiHE greater ftde of every triangle is oppofite to the '* greater angle. Let ABC be a triangle, of which the fide AC is greater than the fide AB ; the angle ABC is alfo greater than the angk BCA. Becaufe AC is... | |
 | Euclid - 1781 - 552 σελίδες
...Therefore any two angles, &c. QED PROP. XVIII. THEO R. THE greater fide of every triangle is oppofite to the greater angle. Let ABC be a triangle, of which the fide AC is greater than the fide AB ; the angle ABC is alfo greater than the angle BC A. B:caufe AC... | |
 | 1798 - 618 σελίδες
...be true that any two sides of a triangle are greater than the third, neither could it be true that the greater side of every triangle is opposite to the greater angle, nor that the equal sides are opposite to equal angles, nor, lastly, that things equal to the same thing... | |
 | Alexander Ingram - 1799 - 374 σελίδες
...Therefore any two angles, &c. QED T PROP. XVIII. THEOR. I HE greater fide of every triangle is oppofitc to the greater angle. Let ABC be a triangle, of which the fide AC is greater than the fide AE ; the angle ABC is alfo greater than the angle BCA, Becaufe AC... | |
 | Robert Simson - 1804 - 530 σελίδες
...therefore any two angles, &c. Q^ED PROP. XVIII. THEOR. THE greater fide of every triangle is oppofite to the greater angle. Let ABC be a triangle of which the fide AC is greater than the fide AB ; the angle ABC is alfo greater than the angle BCA. Becaufe AC... | |
 | Robert Simson - 1806 - 546 σελίδες
...also CAB, ABC, are less than two right angles. Therefore, any two angles, &c. QED PROP. XVIII. THEOR. THE greater side of every triangle is opposite to the greater angle. Let ABC be a triangle, of which A the side AC is greater than the side AB ; the angle ABC is also greater than the angle BCA. , \ n... | |
 | John Playfair - 1806 - 320 σελίδες
...QED PROP. XVIII. THEOR. i THE greater side of every triangle has the greater angle opposite to it. Let ABC be a triangle, of which the side AC is greater than the side AB ; the angle ABC is also greater, than the angle BCA. From AC, which is greater than AB, cut offa AD... | |
 | Euclid - 1810 - 554 σελίδες
...less than two right angles. Therefore any two angles, Sec. QED PROP. XVIII. THEOR. THE greater side,of every triangle is opposite to the greater angle. * * * Let ABC be a triangle, of which ihe side AC is greater than the side AB; the angle ABC is also greater than the angle BCA. Because... | |
 | Charles Hutton - 1811 - 406 σελίδες
...shown that the outward angle ABG, or its equal CBD, is greater than the other angle A. 5TB THEOREM IX. THE Greater Side, of every Triangle, is opposite to the Greater Angle ; and the Greater Angle opposite to the Greater Side. Let ABC be a triangle, having the side AB greater... | |
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