Problems in Elementary PhysicsH. Holt, 1896 - 194 σελίδες |
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Σελίδα 2
... inches 1 meter 1 1 = 39.37 66 66 = 3.28 feet = 1.09 yards 66 1 kilometer = 1 66 .62 miles , or 66 ( nearly ) NOTE ... inch = 2 PROBLEMS IN ELEMENTARY PHYSICS .
... inches 1 meter 1 1 = 39.37 66 66 = 3.28 feet = 1.09 yards 66 1 kilometer = 1 66 .62 miles , or 66 ( nearly ) NOTE ... inch = 2 PROBLEMS IN ELEMENTARY PHYSICS .
Σελίδα 3
Edwin Dana Pierce. Reduction of English to Metric Units . 1 inch = 2.54 centimeters 1 foot = 30.48 66 1 yard = .91 meters ... inches . Value of " g " at New York = 980 cm . or 32.16 ft . STANDARD CONDITIONS for a gas are that the pressure ...
Edwin Dana Pierce. Reduction of English to Metric Units . 1 inch = 2.54 centimeters 1 foot = 30.48 66 1 yard = .91 meters ... inches . Value of " g " at New York = 980 cm . or 32.16 ft . STANDARD CONDITIONS for a gas are that the pressure ...
Σελίδα 4
... inch . How many ( In this and other questions involving both English and metric units see Table of Equivalents on pages 2 and 3. ) 20. 76 cm . equals how many inches ? 21. How many times heavier is the ounce ( avoirdupois 4 PROBLEMS IN ...
... inch . How many ( In this and other questions involving both English and metric units see Table of Equivalents on pages 2 and 3. ) 20. 76 cm . equals how many inches ? 21. How many times heavier is the ounce ( avoirdupois 4 PROBLEMS IN ...
Σελίδα 7
... inches to 1 foot ? 6. Is the ratio of 6 feet to 18 feet correctly expressed thus " ft . " ? Why ? 7. Is the ratio of 150 cm . to 100 cm . a number of centi- meters or not ? If not , what denomination has it ? 8. Can you compare the ...
... inches to 1 foot ? 6. Is the ratio of 6 feet to 18 feet correctly expressed thus " ft . " ? Why ? 7. Is the ratio of 150 cm . to 100 cm . a number of centi- meters or not ? If not , what denomination has it ? 8. Can you compare the ...
Σελίδα 14
... inches . 7. Of one whose diameter is 31 cm . 8. What is the diameter of a rod whose circumference is 15 cm . ? The AREA OF A CIRCLE = πD2 4 where Dthe diameter , or TR2 , where R the radius . 9. Find area of a circle whose diameter is 6 ...
... inches . 7. Of one whose diameter is 31 cm . 8. What is the diameter of a rod whose circumference is 15 cm . ? The AREA OF A CIRCLE = πD2 4 where Dthe diameter , or TR2 , where R the radius . 9. Find area of a circle whose diameter is 6 ...
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amperes angle of incidence barometer block body Boyle's Law brass C₁ candle-power cell centimeter circuit Clark cell coefficient of friction coil concave mirror conjugate foci copper wire cubic current strength deflection density diagram to show diameter direction distance Draw a diagram dynes electric energy equal ergs Express the ratio Find focal length force formula given grams heat horizontal inches index of refraction internal resistance inversely iron lamp latent heat lens liquid magnetic pole mass measure mercury meter Ohm's Law ohms parallel pendulum plane poundal principal focus Prob problems produce Prof proportion represent resultant solid specific gravity square surface tangent galvanometer temperature thick tion total pressure tube units V₁ varies directly velocity of sound vessel vibration-number vibrations per second volts volume watts weight wheel width
Δημοφιλή αποσπάσματα
Σελίδα 1 - Measures of Length. 10 millimeters (mm.) 1 centimeter (cm.) 10 centimeters 1 decimeter (dm.) 10 decimeters 1 meter (m.) 10 meters 1 dekameter (Dm.) 10 dekameters 1 hectometer (Hm.) 10 hectometers 1 kilometer (Km.) 10 kilometers 1 myriameter (Mm.) 1181.
Σελίδα 2 - Measures of Weight 10 milligrams (mg) =1 centigram eg 10 centigrams =1 decigram dg 10 decigrams =1 gram g 10 grams =1 dekagram Dg 10 dekagrams =1 hektogram Hg 10 hektograms =1 kilogram Kg...
Σελίδα 161 - Remembering that the joint resistance of two (or more) circuits in parallel is the reciprocal of the sum of the reciprocals of the resistances of the several branches, we have: Fig.
Σελίδα 156 - ... and the projection of one on the other — is retrograde, or in the same direction as the motion of the hands of a watch.
Σελίδα 124 - A' MB' are similar, and A'B'^B'M AB BM' So in this case, as before, the size of the image is to the size of the object, as the distance of the image from the mirror is to the distance of the object from the mirror.