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Βιβλία Βιβλία 1 - 10 από 20 για Multiply the first term by the power of the ratio, whose exponent is one less than....
" Multiply the first term by the power of the ratio, whose exponent is one less than the number of terms. EXAMPLES. 1. "
Higher Arithmetic: Designed for the Use of High Schools, Academies, and ... - Σελίδα 236
των George Roberts Perkins - 1849 - 342 σελίδες
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An Elementary Treatise on Algebra: To which are Added Exponential Equations ...

Benjamin Peirce - 1837 - 288 σελίδες
...is, the last or nth term is that is, the last term is equal to the product of the first term by that power of the ratio whose exponent is one less than the number of terms. 185. Problem. To find th&~ sum of a geometrical progression, of which the first term, the ratio, and...

An Elementary Treatise on Algebra: To which are Added Exponential Equations ...

Benjamin Peirce - 1837 - 276 σελίδες
...or nth term is / = or»-1; that is, the last term is equal to the product of the first term by that power of the ratio whose exponent is one less than the number of terms. 185. Problem. To -find the sum of a geometrical progression, of which the first term, the ratio, and...

Higher Arithmetic: Designed for the Use of High Schools, Academies, and Colleges

George Roberts Perkings - 1841 - 252 σελίδες
...=4096, this, diminished by one, becomes 4095, which, multiplied by 2048, becomes 8386560; again, the power of the ratio, whose exponent is one less than the number of terms, is 2048, which, multiplied by the ratio, less one, is not changed; .-. 8386560 divided by 2048, gives...

An Elementary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1846 - 258 σελίδες
...number of terms, less one, it follows that the first term is equal to the last term, divided by the power of the ratio, whose exponent is one less than the number of terms. Hence, when we have given the last term, the ratio, and the number of terms, to find the first term,...

An Elemtary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1849 - 347 σελίδες
...progression is 1, the ratio is 2, and the number of terms is 7. What is the last term? In this example, the power of the ratio, whose exponent is one less than the number of terms, is 26=64, which, multiplied by the first term, 1, still remains 64, for the last term. 2. The first...

Higher Arithmetic: Designed for the Use of High Schools, Academies, and ...

George Roberts Perkins - 1850 - 342 σελίδες
...number of terms, less one, it follows .hat the first term is equal to the last term divided by (he power of the ratio whose exponent is one less than the number of terms. Hence, when we have given the last term, the ratio, and the number of terms, to find the first term,...

... An Elementary Arithmetic ... Serving as an Introduction to the Higher ...

George Roberts Perkins - 1850 - 347 σελίδες
...progression is 1, the ratio is 2, and the number of terms is 7. What is the last term? In this example, the power of the ratio, whose exponent is one less than the number of terms, is 26 = 64, which, multiplied by the first term. 1, still remains 64, for the last term. 2. The first...

An Elementary Arithmetic Designed for Academies and Schools: Also Serving as ...

George Roberts Perkins - 1851 - 347 σελίδες
...progression is 1, the ratio is 2, and the number of terms is 7. What is the last term? In this example, the power of the ratio, whose exponent is one less than the number of terms, is 2 e =64, which, multiplied by the first term, 1, still remains 64, for the last term. 3. A person...

An Elementary Arithmetic Designed for Academies and Schools: Also Serving as ...

George Roberts Perkins - 1855 - 347 σελίδες
...progression is 1, the ratio is 2, and the number of terms is 7. What is the last term? In this example, the power of the ratio, whose exponent is one less than the number of terms, is 28=64, which, multiplied by the first term, 1, still remains 64, for the last term. 2. The first...

A Treatise on Algebra

Elias Loomis - 1855 - 316 σελίδες
...That is, 'The last term of a geometrical progression is equal to the product of the first term by that power of the ratio whose exponent is one less than the number of terms. (242.) To find the sum of all the terms of a geometrical progression. If we take any geometrical series,...




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