First Course in Algebra, Βιβλίο 1Macmillan, 1919 - 334 σελίδες |
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Αποτελέσματα 1 - 5 από τα 37.
Σελίδα 1
... suppose 1-2 ft . and b = 3 ft . , it gives instantly A = 2 × 3 , or 6 sq . ft . , which we know by arithmetic is the right answer . The advantage in using letters is twofold . It enables us to write general rules and it is of great ...
... suppose 1-2 ft . and b = 3 ft . , it gives instantly A = 2 × 3 , or 6 sq . ft . , which we know by arithmetic is the right answer . The advantage in using letters is twofold . It enables us to write general rules and it is of great ...
Σελίδα 14
... sides , 8x = 16 . Dividing both sides by 8 , x = 2 . Ans . Again , suppose we wish to solve the equation . 6 + 6x = 3x + 12 . ( Axiom I ) ( Axiom IV ) Here we proceed as follows . sides , Subtracting 6 14 [ I , § 11 FIRST COURSE IN ALGEBRA.
... sides , 8x = 16 . Dividing both sides by 8 , x = 2 . Ans . Again , suppose we wish to solve the equation . 6 + 6x = 3x + 12 . ( Axiom I ) ( Axiom IV ) Here we proceed as follows . sides , Subtracting 6 14 [ I , § 11 FIRST COURSE IN ALGEBRA.
Σελίδα 35
... suppose another case . Suppose you are $ 2 in debt when you accidentally break a window valued at $ 5 . Even though you have no money to pay for it at the moment , you really have had $ 5 taken away , or subtracted from you . It is just ...
... suppose another case . Suppose you are $ 2 in debt when you accidentally break a window valued at $ 5 . Even though you have no money to pay for it at the moment , you really have had $ 5 taken away , or subtracted from you . It is just ...
Σελίδα 36
... suppose you have $ 10 , but wish to buy a picture costing $ 15 . This is like taking away , or subtracting , $ 15 from yourself when you have only $ 10 , and the result is that you go $ 5 into debt . It is the same as adding a $ 15 debt ...
... suppose you have $ 10 , but wish to buy a picture costing $ 15 . This is like taking away , or subtracting , $ 15 from yourself when you have only $ 10 , and the result is that you go $ 5 into debt . It is the same as adding a $ 15 debt ...
Σελίδα 40
... suppose that 5X ( -4 ) = ( - 4 ) × 5 . But this last form ( being similar to the one in the second case ) means -4 taken 5 times , which is 20. Thus , we have 5X ( −4 ) = − 20 . ( 4 ) Consider the product ( -5 ) X ( -4 ) . We ...
... suppose that 5X ( -4 ) = ( - 4 ) × 5 . But this last form ( being similar to the one in the second case ) means -4 taken 5 times , which is 20. Thus , we have 5X ( −4 ) = − 20 . ( 4 ) Consider the product ( -5 ) X ( -4 ) . We ...
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a²+2ab+b² ab+b² added algebra Appendix arithmetic Axiom called cents CHAPTER check your answer circle coefficient common denominator common factor completing the square cube diameter divisor Draw the graph equal EXAMPLE EXERCISES Solve figure Find the H. C. F. Find the numbers Find the value following equations following exercises following expressions fraction further exercises given equation gives highest common factor HINT illustrated inches length lowest common means miles an hour minuend monomial multiply negative numbers numerator and denominator ORAL EXERCISES parentheses perfect square polynomial quadratic quadratic equation quotient radical radicand radius ratio represents result Similarly Simplify simultaneous equations SOLUTION Solve the equation square root subtract subtrahend SUPPLEMENTARY EXERCISES surd Transposing triangle trinomial weight wheel write WRITTEN EXERCISES x²y² yards