...fécond by 19, leaves the golden number ; the third by 15 leaves the indiftion. .Then if the fum of thefe numbers be divided by 7980, the remainder will be...year of the Julian period required. Or, the cycle of the fun, 18, muft be multiplied by 4845; the golden number, 8, by 4200; and the indiiUon, 10, by...

...fecond by 19 leaves the golden number, the third by 15 leaves the indiftion. Then if the fum of thefe numbers be divided by 7980, the remainder will be...period required. Or, The cycle © 18 mult, by 4845 = 87110^ The fum of Golden numb. 8 - 4100 r= 33600 >• the products Indiction to - 6916 =: 691603...

...moon, and 6916 by the year of the cycle of the indiction, and the sum of these three products being divided by 7980, the remainder will be the year of the Julian period, EXAMPLE. Let the solar cycle be 21, lunar cycle 19, and indiction 7 : required the corresponding year...

...second by 1 9 leaves the golden number, the third by ] 5 leaves the indiction. Then if the sum of these numbers be divided by 7980, the remainder will be...year of the Julian period required. Or, The cycle 0 18 mult, by 4845 = 87210 } The ^ Qf fte Golden numb. 8 4200 = 33600 £ ^ ¡s £ Indiction 10 6916...

...corresponding to certain given years of the Cycles of the Sun, Moon, and Indiction. sum of the products by 7980 : the remainder will be the year of the Julian Period required. Thus, if we repeat the foregoing example of the given years of the three cycles, AD 1. S 10 x 4845...

...Christian era. To determine the number for any year. Eule. — Add 4713 to the given year; divide the sum by 7980 ; the remainder will be the year of the Julian Period. Or for any year from the present time up to the year 3267, Tear of the Julian Period = 6513 + (Tear...