 | Thomas Sherwin - 1841 - 314 σελίδες
...second term of the root, also at the right of the divisor. Multiply the divisor, with the term annexed, by the second term of the root, and subtract the product from the dividend. 4. The remainder will form a new dividend, which is to be divided by twice the whole root... | |
 | William Scott - 1844 - 568 σελίδες
...term of the root. Multiply the algebraic sum of double the first and once the second term of the root by the second term of the root, and subtract the product...; divide the first term of the second remainder by double the first term of the root; the quotient is the third term of the root. Multiply the algebraic... | |
 | Ormsby MacKnight Mitchel - 1845 - 308 σελίδες
...first term of the root, by the second term, plus the square of the second term. Multiply the complete divisor by the second term of the root, and subtract the product from the remainder, and bring down the next remainder. Divide the first term of this remainder by three times... | |
 | Charles William Hackley - 1846 - 544 σελίδες
...the second term of the root), with its proper sign, to the divisor. 5°. Multiply the whole of this divisor by the second term of the root, and subtract the product from the first remainder. 6°. Divide this second remainder by twice the sum of the first two terms of the root already found,... | |
 | Joseph Ray - 1848 - 250 σελίδες
...found, and annex the result both to the root and the divisor. Multiply the divisor thus increased, by the second term of the root, and subtract the product from the remainder. 3d. Double the terms of the root already found, for a partial divvsor, and divide the first... | |
 | James Elliot - 1850 - 116 σελίδες
...must be annexed with its proper sign, as also to the divisor. 4. Multiply the divisor, thus enlarged, by the second term of the root, and subtract the product from the last dividend. 5. To the remainder bring down two more terms of the given quantity, and use that as... | |
 | Joseph Ray - 1852 - 408 σελίδες
...already found, and annex the result to both the root and the divisor. Multiply the divisor thus increased by the second term of the root, and subtract the product from the remainder. 3rd. Double the terms of the root already found for a partial divisor] then divide the first... | |
 | G. Ainsworth - 1854 - 216 σελίδες
...quotient, and also annexed to the new divisor as a second term. Multiply the new divisor by the last found term of the root, and subtract the product from the first remainder. To the new remainder bring down the two following terms of the compound quantity for a new dividend,... | |
 | Thomas Sherwin - 1855 - 262 σελίδες
...second term of the root, also at the right of the divisor. Multiply the divisor, with the term annexed, by the second term of the root, and subtract the product from the dividend. 4. The remainder will form a second dividend, which is to be divided by twice the whole root... | |
 | Theodore Strong - 1859 - 570 σελίδες
...root to the incomplete divisor, and the result will be the complete divisor. Multiply the complete divisor by the second term of the root, and subtract the product from the first remainder, cutid the result will constitute the second remainder. 3. Take twice the root now fmmd for the incomplete... | |
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Multiply the divisor thus increased, by the second term of the root, and subtract the product from the remainder. 
