 | 1801 - 658 σελίδες
...30 • Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . From 8 times the chord of half the arc subtract the chord of the whole arc, and ~ of the remainder "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius... | |
 | Samuel Webber - 1808 - 466 σελίδες
...3'1416 9 As 180 : 30 Or 6 : 1 : : 282744 ; 4'7124 Or a : 30 : : '05236x9 : 4'7124 36 4'? 124 the answer. RULE*. From 8 times the chord of half the arc subtract the chord of the whole arc, and | of the remainder will be. the kpgth, of the arc nearly. * DEM0NSTRATI0N. Let the radius CA=r,... | |
 | Anthony Nesbit, W. Little - 1822 - 916 σελίδες
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. 8 times the chord of half the arc subtract the chord of the whole ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
 | Anthony Nesbit - 1824 - 476 σελίδες
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. From 8 times the chord of half the arc subtract the chord of the whole arc, and }, of the remainder . will be the length of the arc, nearly. Kote. Half the chord of the whole... | |
 | John Nicholson - 1825 - 822 σελίδες
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 39 : : '05236 x 9 : 47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of viie arc nearly. Ex. 2. The chord AB (Proli. 8.) of the... | |
 | John Nicholson (civil engineer.) - 1825 - 1008 σελίδες
...: 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 4-7124 90 4*7124 the answer. R'i!,- 2. From 8 times the chord of half the arc subtract the chord of tbe whole arc, and ' of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prol.... | |
 | William Galbraith - 1827 - 412 σελίδες
...radius of the circle multiplied by 0.0174533 and by the number of degrees in the arc. Or, from eight times the chord of half the arc subtract the chord of the whole arc, one third of this remainder is the length of the arc nearly. 9. Circular Sector. — The area is equivalent to the... | |
 | John Nicholson (Civil engineer) - 1830 - 240 σελίδες
...As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 σελίδες
...in the same square whose diameter is 24. PROBLEM IX. To find the length of a Circular Arc. RULE 1. From 8 times the chord of half the arc subtract the chord of the whole arc, and ^ of the difference will be the length of the arc, nearly. RULE 2. Multiply the number of degrees... | |
 | Francis Walkingame - 1833 - 204 σελίδες
...5. The area X'6S6G197) Problem 9- Toßnd the length of a circular arc RULE 1. From 8 times Fig. 8. the chord of half the arc subtract the chord of the whole arc, and ¿ of the difference will be the length of the arc, nearly. That is ADx8— AB -т-3=.агс ADB.... | |
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From 8 times the chord of half the arc, subtract the chord of the whole arc ; one-third of the remainder will be the length of the arc nearly. 
