 | Robert Simson - 1762 - 488 σελίδες
...the angle f. if. i. DTY is equal f to the angle GTS. therefore in the triangles DTY, GTS there are two angles in the one equal to two angles in the other, aid one fide equal to one fide, oppolite to two of the equal angles-, viz. DY to GS ; for they are... | |
 | Robert Simson - 1775 - 534 σελίδες
...and the angle l)TY is equal f to the angle G PS : Therefore in the triangles D l"Y, GTS tlv;re are two angles in the one equal to two angles in the other, and one lide equal to one fide, oppofite to two of the equal angles, viz.. DY to GS ; for they are... | |
 | Euclid - 1781 - 552 σελίδες
...equal c ; and the angle DTY is equal t to the angle GTS : Therefore in the triangles DTY, GTS there are two angles in the one equal to two angles in the other, and one fide equal to one^fide, oppofite to two of the equal angles, viz. DY to GSj for they arc the... | |
 | Euclid, John Playfair - 1795 - 462 σελίδες
...angles AED, CEB are equal a, and alfo the alternate angles EAD, ECB b, the triangles ADE, CEB have two angles in the one equal to two angles in the other, each to each : but the fides AD arid BC, which are opppfite tp equal angles in thefe trier 34. i. angles,... | |
 | George Gregory - 1796 - 620 σελίδες
...equal to GDC, QpM is equal to GDB but GDB is equal to MDq; in the two triangles QJD M, MD q, there are two angles in the one equal to two angles in the other, and one fide MD common to both, therefore QJM will be equal to My. The fame may be proved alfo of the... | |
 | Robert Simson - 1804 - 530 σελίδες
...equal c ; and the angle DTY is equal f to the angle GTS. therefore in the triangles DTY, GTS there are two angles in the one equal to two angles in the other, and one fide equal to one fide, oppofite to two of the equal angles, viz. DY to GS; for they are the... | |
 | Charles Hutton - 1811 - 406 σελίδες
...parts, or triangles. AB For, since the sides AB and DC are parallel, as also the sides AD and Be (defin. 32), and the line BD meets them ; therefore the alternate...triangles, having two angles in the one equal to two anglei in the other, have also their third angles equal (cor. 1, th. 11), namely, the angle A equal... | |
 | Charles Hutton - 1812 - 620 σελίδες
...-j. For, since the sides AB and DC are pa- .»• rallcl, as also the sides AD and BC (defin. 3a), and the line BD meets them ; therefore the alternate...the other, have also their third angles equal (cor. l,th. 17), namely, the angle A equal to the angle c, which are two of the opposite angles of the parallelogram.... | |
 | Charles Hutton - 1816 - 610 σελίδες
...parts, or triangles. For, since the sides AB and DC are parallel, as also the sides AD and BC (defin. 32), and the line BD meets them ; therefore the alternate...equal (th 12), namely, the angle ABD to the angle a DB, and the angle AUDIO the angle CBD. Hence the two triangles, having two angles in the one equal... | |
 | Charles Hutton - 1818 - 646 σελίδες
...parts, or triangles. For, since the sides AB and nc are parallel, as also the sides AD and BC (delin. 32), and the line BD meets them ; therefore the alternate angles are equal (th. 12j, namely, the angle ABD to the angle CDB, and the angle ADB to the angle CUD. Hence the two triangles,... | |
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EBF, there are two angles in the one equal to two angles in the other, each to each ; and the... 
