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2. Add 12 rd. 4 yd. 2 ft. 8 in.; 16 rd. 2 yd. 1 ft. 10 in.; 19 rd. 5 yd. 11 in.; 9 rd. 3 yd. 2 ft. 9 in.

3. Add 8 mi. 42 rd. 3 yd. 2 ft. 9 in.; 7 mi. 14 rd. 13 ft. 8 in.; 16 mi. 14 rd. 7 in.; 32 rd. 2 yd. 9 in.

4. From 21 mi. 125 rd. 5 yd. 1 ft. 9 in. take 10 mi. 136 rd. 2 yd. 2 ft. 7 in.

7 in. from 9 in. = 2 in., which we write under the column of inches. Since 2 ft. cannot be taken from 1 ft., we take 1 yd. (1 yd. = 3 ft.) and add it to the 1 ft., thus making 4 ft. 2 ft. from 4 ft. 2 ft., which

we write under the column of feet. 2 yd.

OPERATION

mi. rd. yd. ft. in.
21 125 5 19

10

136 2 2 7

10 309 2 2 2 Ans.

=

320 rd.)

from 4 yd. = 2 yd., which we write under the column of yards. Since 136 rd. cannot be taken from 125 rd., we take 1 mi. (1 mi. and add it to the 125 rd., thus making 445 rd. 136 rd. from 445 rd. 309 rd., which we write under the column of rods. 10 mi. from 20 mi. = 10 mi.

LESSON 94

=

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4. Subtract 32 mi. 310 rd. 3 yd. 2 ft. 9 in. from 84 mi.

5 yd.

5. Subtract 39 mi. 12 ft. 6 in. from 126 mi. 1 rd. 1 yd. 1 ft.

6. Multiply 3 mi. 59 rd. 3 yd. 5 ft. 8 in. by 7.

7 times 8 in. = 56 in. = 4 ft. 8 in. We write the 8 in. under the inches, and add the 4 ft. to the product of feet. 7 times 5 ft., plus 4 ft. (7 x 5 ft.) + 4 ft. 39 ft. = 13 yd. We write a cipher under feet, and add the

=

OPERATION

mi. rd. yd. ft. in.
3 59 3 5 8

7

22 99 1

0

8 Ans.

=

13 yd. to the product of yards. 7 times 3 yd., plus 13 yd. (7 × 3 yd.) + 13 yd. 34 yd. = 6 rd. 1 yd. We write the 1 yd. under yards, and add the 6 rd. to the product of rods. 7 times 59 rd., plus 6 rd. (7 × 59 rd.) + 6 rd. = 419 rd. 1 mi. 99 rd. We write the 99 rd. under rods, and add the 1 mi. to the product of miles. 7 times 3 mi., plus 1 mi. (7 × 3 mi.) + 1 mi. 22 mi., which we write under miles. Multiply:

7.

=

8.

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9.

rd. yd. ft.

18 120 2 9

10. Multiply 60 mi. 240 rd. 9 ft. by 9.
11. Multiply 120 mi. 4 yd. 2 ft. 7 in. by 7.
12. Multiply 17 mi. 42 rd. 13 ft. 8 in. by 8.

LESSON 95

1. Divide 129 mi. 50 rd. 7 ft. by 8.

of 129 mi. = 16 mi., and 1 mi. remaining. We write the 16 mi. in the quotient under miles, and change the 1 mi. to its equivalent, 320 rd., which we

50 rd., thus making 370 rd.

add to the

of 370 rd.

8)129

OPERATION

296

mi. rd. ft.
50 7

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= 46 rd., and 2 rd. remaining. We write the 46 rd. under rods, and change the 2 rd. to its equivalent, 33 ft., which added to 7 ft. make 40 ft. of 40 ft. = 5 ft., which we write in the quotient under feet.

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9. Multiply 3 mi. 90 rd. 2 yd. 4 ft. 7 in. by 6.

10. Find of 21 rd. 3 yd. 4 ft. 8 in.

11. Find .25 of 17 rd. 4 yd. 7 ft. 10 in.

12. Find 25% of 5 mi. 310 rd. 5 yd. 2 ft.

13. How many steps, each 2 ft. 8 in. long, will a man take in walking 5 miles?

14. How much will 36 ft. of wire fencing cost at $1.20 per rod?

15. If 18 seconds intervene between the flash and report of a gun, what is its distance, the velocity of sound being 1090 ft. per second? Answer in miles, rods, and feet.

16. If a horse can trot 280 rd. in 3 minutes, how far, at the same rate, would he travel in 10 minutes?

LESSON 96

1. For what is Surveyors' Linear Measure used?
2. Recite the table of surveyors' linear measure.
3. How many links are there in 2 ch.? In 4 rd.?
4. How many inches are there in a chain?

5. 50 li. equal how many rods? How many feet are there in 50 li. ?

Gunter's chain, named after its inventor, Edmund Gunter, is 792 in. long, or 66 ft., or 4 rd. Surveyors generally use a chain or tape 100 ft. long.

6. For what is Surface or Square Measure used? 7. Recite the table of surface or square measure. 8. How many square feet are there in 4 sq. yd.? 9. 36 sq. ft. equal how many square yards? 10. 12 sq. in. equal what part of a square foot? 11. 36 sq. in. equal what part of a square foot?

12. 36 sq. in. equal what per cent of a square foot? 13. How many square rods are there in 21 A.?

14. 25% of an acre equals how many square rods?

15. How many square inches are there in 121% of a square foot?

16. How many square rods are there in 75% of an acre ? 17. How many square feet are there in 331% of 2 sq. yd.? 18. 12 mi. equal how many chains? 40 ch. equal how many rods?

19. How many links and inches are there in 240 in.? 20. How many chains and links are there in 760 li. ? 21. A piece of land is 5 ch. 50 li. long. How many feet long is it?

22. Change 9 sq. yd. 4 sq. ft. 27 sq. in. to square inches.

23. Change 4 A. 20 sq. rd. 25 sq. yd. to square feet. 24. Change 129600 sq. in. to square yards.

25. Change to square rods: 151 sq. yd., 121 sq. yd., 21% of 1 acre.

LESSON 97

A Solid or Volume is that which has the dimensions length, breadth, and thickness or height.

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A Rectangular Solid is one that is bounded by six rectangles.

A Cube is a solid that is bounded by six equal squares.

1. For what is Cubic, or Solid Measure used?

2. Recite the table of cubic, or solid, measure.

3. How many cubic yards are there in 81 cubic feet? 4. How many cubic feet are there in

5. How many cubic feet are there in

of a cubic yard?

of a perch?

6. 33% of a cubic yard equals how many cubic feet? 7. Change 16 cu. yd. 13 cu. ft. 24 cu. in. to cubic inches. 8. Change 1760 cu. yd. to cubic feet.

9. How many cubic yards are there in 288 cu. ft.?

A Cord of Wood is usually represented by a pile 8 ft. long, 4 ft. wide, and 4 ft. high. It, therefore, contains 8 x 4 x 4, or 128 cu. ft. See p. 138.

A Perch of Stone or masonry is 161 ft. long, 1 ft. wide, and 1 ft. high, and contains 161 × × 1, or 242 cu. ft. 10. Change 151 cu. yd. 19 cu. ft. to cords.

11. Divide 193 cu. yd. 26 cu. ft. 329 cu. in. by 8. 12. Add 8 cu. yd. 1240 cu. in., 23 cu. yd. 163 cu. ft. 13. Subtract 74 A. 131 sq. rd. 10 sq. yd. 8 sq. ft. 120 sq. in. from 95 A. 116 sq. rd. 25 sq. yd. 2 sq. ft. 15 sq. in.

14. Multiply 4 cords 18 cu. ft. 844 cu. in. by 7.

LESSON 98

1. For what is Liquid Measure used?

The standard unit is the gallon. It contains 231 cu. in.

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