 | Peter Nicholson - 1823 - 210 σελίδες
...rectangle is said to be contained by two of its sides, about any one of its angles. THEOREM 52. 147. The area of a parallelogram is equal to the product of its base and altitude. For the parallelogram ABCD is equal to the rectangle ABEF, which has the same base AB, and the same... | |
 | Nicholas Tillinghast - 1844 - 108 σελίδες
...parallelogram is equivalent to a rectangle which has an equal base and equal altitude. Cor. 2. Hence the area of a parallelogram is equal to the product of its base by its altitude (Prop. 1).* Cor. 3. Hence parallelograms of equal altitudes, are in proportion... | |
 | Thomas Tate (mathematical master.) - 1848 - 284 σελίδες
...are understood to mean the number of linear units contained in them. In this sense, therefore, we say that the area of a parallelogram is equal to the product of the base by the perpendicular. As a triangle is one-half the parallelogram having the same base and... | |
 | Elias Loomis - 1849 - 252 σελίδες
...the base, and the other the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Cor. Parallelograms of the same base are to each other as their altitudes, and... | |
 | Adrien Marie Legendre - 1852 - 436 σελίδες
...square on a single one ; on a triple line it is nine times as great, &c. E PROPOSITION V. THEOEEM. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram, and BE its altitude : then will its area be equal to ABxBE. Draw Af]... | |
 | Charles Davies - 1854 - 436 σελίδες
...the square on a single one ; on a triple line it is nine times as great, &c. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram, and BE its altitude: then will its area be equal to AB x BE. Draw BE... | |
 | John Radford Young - 1855 - 218 σελίδες
...a parallelogram, and CE its altitude ; then, in the right-angled triangle AEC, we shall have _^* BO that the area of a parallelogram is equal to the product of any two adjacent sides multiplied by the sine of the angle between them. The trouble of finding the... | |
 | Charles Davies, William Guy Peck - 1855 - 628 σελίδες
...is an equilateral parallelogram or rhojnbus. The diagonals of a rectangle are equal to each other. The area of a parallelogram is equal to the product of its base by its altitude. Any two parallelograms having the same or equal bases are to each other as their... | |
 | Peter Nicholson - 1856 - 518 σελίδες
...rectangle is said to be contained by two of its sides, about any one of its angles. THEOREM 43. 111. The area of a parallelogram is equal to the product of its base and altitude. For the parallelogram ABCD is equal to the rectangle ABEF, which has the same base AB, and the same... | |
 | Adrien Marie Legendre, Charles Davies - 1857 - 442 σελίδες
...as the square on a single one ; on a triple line it is nine times as great, PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its boat and altitude. Let ABCD be any parallelogram, and BE its altitude: then will its area be equal... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
