 | Charles Hutton - 1770 - 518 σελίδες
...trapezoide will be infinite, and it is then called, fometimes, a cylindroid. GENERAL RULE. To the fum of the areas of the two ends add four times the area of a fection parallel to and equally diftant from both ends, multiply the laft fum by the height and i... | |
 | John McGregor (teacher of mathematics.) - 1792 - 532 σελίδες
...being 72 feet. Anf. 89.5356 cubit-feet. , PROBLEM IX. Tcjlnd the folidity of the prifmoid. RULE I. To the areas of the two ends add four times the area of the middle feâion. Multiply the fum by the height, and $ the produft will be the folidity. RULE 2. To the longeft... | |
 | Thomas Keith - 1817 - 306 σελίδες
...*2618 (one-third of '7854), and then by the height, the last product will be the solidity. RULE II*. To the sum of the areas of the two ends, add four times the area of a section parallel to. * The first Rule, which is the same is that given for the priimoid, wai introduced... | |
 | Anthony Nesbit, W. Little - 1822 - 916 σελίδες
...bushels. PROBLEM IX. 'To find the content of a vessel in the form of a prismoid, RULE, By the Pen. To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from both ends ; multiply this sum by the perpendicular... | |
 | Anthony Nesbit - 1824 - 476 σελίδες
...perpendicular height 9 feet ? Ans. 82.6875 feet. PROBLEM X. To find the solidity of a prismoid. RULE. To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends ; multiply this sum by the perpendicular height,... | |
 | Thomas Curtis - 1829 - 878 σελίδες
...in many cases it gives very erroneous results. The true method of finding the solidity is this : to the sum of the areas of the two ends, add four times the area of the middle section between them, and the sum multiplied by onelixth of the length will give the solidity. Thus, in the... | |
 | Thomas Curtis - 1829 - 810 σελίδες
...7140 solid inches, or 4-1319 solid feet. PROB. XXIX. To find the solidity of a promoid. Rule,— to the sum of the areas of the two ends add four times the area of a section parallel to, and equally distant from, both ends, and multiply the sum by one-tenth of the... | |
 | John Bonnycastle - 1829 - 256 σελίδες
...to be 17.14508 inches ? Ans. 3.1006 feet. PROBLEM XI. To find the solidity ofaprismoid. . RULE.* To the sum of the areas of the two ends add four times the area of a section parallel tq and equally distant from both ends, and this last sum multiplied by £ of the... | |
 | Jeremiah Day - 1831 - 520 σελίδες
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT. Let L and... | |
 | Jeremiah Day - 1831 - 418 σελίδες
...what is the solidity ? Ans. 5040. PROBLEM VIII. Tofint} the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY i OF THE HEIGHT. Let L and... | |
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RULE. To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends ; multiply this sum by the perpendicular height, and J of the product will be the solidity. 
