The Complete ArithmeticH.I. Gourley, Agt., 1876 - 452 σελίδες |
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Σελίδα iii
... problems have been chosen with special reference to the wants of our American youth . And while we do not claim perfection in this matter , we do think we have taken a step in the right direction . We believe that no man whose son is to ...
... problems have been chosen with special reference to the wants of our American youth . And while we do not claim perfection in this matter , we do think we have taken a step in the right direction . We believe that no man whose son is to ...
Σελίδα v
... Problems 59 Division 151 OUTLINE of Division 60 Review Problems . 157 Division 61 Converse Reductions 162 Problems Under the Four Rules ... 73 Aliquot Parts ... 164 Bills . 167 CHAPTER II . DECIMALS . CHAPTER IV . DENOMINATE NUMBERS ...
... Problems 59 Division 151 OUTLINE of Division 60 Review Problems . 157 Division 61 Converse Reductions 162 Problems Under the Four Rules ... 73 Aliquot Parts ... 164 Bills . 167 CHAPTER II . DECIMALS . CHAPTER IV . DENOMINATE NUMBERS ...
Σελίδα ix
... problems . By means of Section Maps of the Western States , the pupil may locate the principal cities , towns , etc. 214. The edge of a cube is one of its dimensions . The edge of any solid is a line formed by the meeting of two ...
... problems . By means of Section Maps of the Western States , the pupil may locate the principal cities , towns , etc. 214. The edge of a cube is one of its dimensions . The edge of any solid is a line formed by the meeting of two ...
Σελίδα x
... problems . 461. Pupils should also be exercised in solving Problems in Partnership and Bankruptcy by Distributive Proportion , pp . 285-288 . 484. Prob . 1. Had Simpson paid the stipulated sums at the times agreed upon , the party from ...
... problems . 461. Pupils should also be exercised in solving Problems in Partnership and Bankruptcy by Distributive Proportion , pp . 285-288 . 484. Prob . 1. Had Simpson paid the stipulated sums at the times agreed upon , the party from ...
Σελίδα 13
... Problem is a question for solution . 15. An Explanation is a statement of the reasons for the manner of solving a problem . 16. A Principle is a general truth upon which a process of computation is founded . 17. An Example is a problem ...
... Problem is a question for solution . 15. An Explanation is a statement of the reasons for the manner of solving a problem . 16. A Principle is a general truth upon which a process of computation is founded . 17. An Example is a problem ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
1ST SOLUTION 2D SOLUTION acres amount angle bank barrel base bought bricks bushels ciphers Compound compound interest contained cost cube cube root cubic denominate number diameter discount Divide dividend divisor dollars Dry Measure equal EXAMPLE 2.-What EXPLANATION.-Since EXPLANATION.-We face factors feet figure Find the sum fraction frustum gain gallons greatest common divisor Hence hundred hundredths hypotenuse inches insured integers interest of $1 least common multiple measure miles mills minuend Multiply paid par value payment Percentage Pittsburgh pounds premium Present Worth principal PROBLEMS quires quotient rate per cent ratio Reduce remainder Rule selling slant height sold SOLUTION.-Since square root subtract subtrahend thick thousand thousandths Troy Troy Weight units weight wheat whole number write Written Exercises Written Exercises+ yards
Δημοφιλή αποσπάσματα
Σελίδα 200 - TIME 60 seconds (sec.) = 1 minute (min.) 60 minutes =1 hour (hr.) 24...
Σελίδα 197 - A circle is a plane figure bounded by a curved line, every point of which is equally distant from a point within called the center.
Σελίδα 121 - The Least Common Multiple of two or more numbers is the least number that...
Σελίδα 420 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.
Σελίδα 398 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until all the periods are brought down. NOTE.
Σελίδα 195 - Dry Measure 2 pints (pt.) =1 quart (qt.) 8 quarts = 1 peck (pk.) 4 pecks = 1 bushel (bu.) 2150.42 cu.
Σελίδα 389 - ... by the last figure of the root, and subtract the product from the dividend ; to the remainder bring down the next period for a new dividend.
Σελίδα 426 - WEIGHTS. 10 milligrammes = 1 centigramme. 10 centigrammes = 1 decigramme. 10 decigrammes = 1 gramme. 10 grammes = 1 decagramme. 10 decagrammes = 1 hectogramme. 10 hectogrammes = 1 kilogramme. 10 kilogrammes = 1 myriagramme.
Σελίδα 197 - An ACUTE ANGLE is one which is less than a right angle ; as the angle DEF.
Σελίδα 72 - Place the sum down as in the last example, then mark off from the right of the dividend as many figures as there are ciphers in the divisor...