The Complete ArithmeticH.I. Gourley, Agt., 1876 - 452 σελίδες |
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Σελίδα 13
... Solution , Problem , Explanation , Principle , Example , Analysis , and Rule . 13. A Solution is a process of computation used to obtain a required result . 14. A Problem is a question for solution . 15. An Explanation is a statement of ...
... Solution , Problem , Explanation , Principle , Example , Analysis , and Rule . 13. A Solution is a process of computation used to obtain a required result . 14. A Problem is a question for solution . 15. An Explanation is a statement of ...
Σελίδα 42
... SOLUTION . Minuend , 54 Subtrahend , 19 Remainder , 35 EXPLANATION . - It is evident that we cannot subtract 9 ones from 4 ones . But by adding 10 ones to the minuend and 1 ten ( 10 ones ) to the subtrahend ( 76 ) , we can perform the ...
... SOLUTION . Minuend , 54 Subtrahend , 19 Remainder , 35 EXPLANATION . - It is evident that we cannot subtract 9 ones from 4 ones . But by adding 10 ones to the minuend and 1 ten ( 10 ones ) to the subtrahend ( 76 ) , we can perform the ...
Σελίδα 51
... solution of problems which contain concrete numbers , the number used concretely is the true multiplicand . Thus , 4 ... SOLUTION . By Addition . Parts , { 564 564 564 Sum , 1692 SOLUTION . - EXPLANATION . - In the Solution by Addition ...
... solution of problems which contain concrete numbers , the number used concretely is the true multiplicand . Thus , 4 ... SOLUTION . By Addition . Parts , { 564 564 564 Sum , 1692 SOLUTION . - EXPLANATION . - In the Solution by Addition ...
Σελίδα 57
... SOLUTION . 3250 50 162500 EXPLANATION . - 5 times 3250 is 5 times 325 with a cipher annexed , or 16250 , and 50 times 3250 is 16250 with one cipher annexed , or 162500 , the re- quired product . 95. RULE . - To the product of all the ...
... SOLUTION . 3250 50 162500 EXPLANATION . - 5 times 3250 is 5 times 325 with a cipher annexed , or 16250 , and 50 times 3250 is 16250 with one cipher annexed , or 162500 , the re- quired product . 95. RULE . - To the product of all the ...
Σελίδα 63
... SOLUTION . - Since 2 dollars are contained in 10 dollars 5 times , he can buy 5 books . Or , 2 dollars are contained in 10 dollars 5 times . Therefore , he can buy 5 books . Second . EXAMPLE . — If a man divides 10 dollars equally ...
... SOLUTION . - Since 2 dollars are contained in 10 dollars 5 times , he can buy 5 books . Or , 2 dollars are contained in 10 dollars 5 times . Therefore , he can buy 5 books . Second . EXAMPLE . — If a man divides 10 dollars equally ...
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Συχνά εμφανιζόμενοι όροι και φράσεις
1ST SOLUTION 2D SOLUTION acres amount angle bank barrel base bought bricks bushels ciphers Compound compound interest contained cost cube cube root cubic denominate number diameter discount Divide dividend divisor dollars Dry Measure equal EXAMPLE 2.-What EXPLANATION.-Since EXPLANATION.-We face factors feet figure Find the sum fraction frustum gain gallons greatest common divisor Hence hundred hundredths hypotenuse inches insured integers interest of $1 least common multiple measure miles mills minuend Multiply paid par value payment Percentage Pittsburgh pounds premium Present Worth principal PROBLEMS quires quotient rate per cent ratio Reduce remainder Rule selling slant height sold SOLUTION.-Since square root subtract subtrahend thick thousand thousandths Troy Troy Weight units weight wheat whole number write Written Exercises Written Exercises+ yards
Δημοφιλή αποσπάσματα
Σελίδα 200 - TIME 60 seconds (sec.) = 1 minute (min.) 60 minutes =1 hour (hr.) 24...
Σελίδα 197 - A circle is a plane figure bounded by a curved line, every point of which is equally distant from a point within called the center.
Σελίδα 121 - The Least Common Multiple of two or more numbers is the least number that...
Σελίδα 420 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.
Σελίδα 398 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until all the periods are brought down. NOTE.
Σελίδα 195 - Dry Measure 2 pints (pt.) =1 quart (qt.) 8 quarts = 1 peck (pk.) 4 pecks = 1 bushel (bu.) 2150.42 cu.
Σελίδα 389 - ... by the last figure of the root, and subtract the product from the dividend ; to the remainder bring down the next period for a new dividend.
Σελίδα 426 - WEIGHTS. 10 milligrammes = 1 centigramme. 10 centigrammes = 1 decigramme. 10 decigrammes = 1 gramme. 10 grammes = 1 decagramme. 10 decagrammes = 1 hectogramme. 10 hectogrammes = 1 kilogramme. 10 kilogrammes = 1 myriagramme.
Σελίδα 197 - An ACUTE ANGLE is one which is less than a right angle ; as the angle DEF.
Σελίδα 72 - Place the sum down as in the last example, then mark off from the right of the dividend as many figures as there are ciphers in the divisor...