The First Six Books: Together with the Eleventh and TwelfthJ. Balfour, 1781 - 520 σελίδες |
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Αποτελέσματα 1 - 5 από τα 83.
Σελίδα 29
... fame reason , the ex- terior angle CEB of the triangle ABE is greater than BAC ; and it has been demonftrated that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC . Therefore , if ...
... fame reason , the ex- terior angle CEB of the triangle ABE is greater than BAC ; and it has been demonftrated that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC . Therefore , if ...
Σελίδα 40
... fame bafe and between the fame parallels , are equal to one another , PAR ... reafon EF is equal to BC ; wherefore AD is equal b to EF ; and DE is common ... fame trapezium take the triangle EAB ; the remain- ders therefore are ...
... fame bafe and between the fame parallels , are equal to one another , PAR ... reafon EF is equal to BC ; wherefore AD is equal b to EF ; and DE is common ... fame trapezium take the triangle EAB ; the remain- ders therefore are ...
Σελίδα 41
... fame parallels , are equal to one another . PA Let ABCD , EFGH be bet parallelograms upon e qual bafes BC , FG , and ... reafon , the parallelogram EFGH is equal to the fame EBCH : Therefore alfo the parallelogram ABCD is equal to ...
... fame parallels , are equal to one another . PA Let ABCD , EFGH be bet parallelograms upon e qual bafes BC , FG , and ... reafon , the parallelogram EFGH is equal to the fame EBCH : Therefore alfo the parallelogram ABCD is equal to ...
Σελίδα 45
... fame reafon , the triangle KGC is equal to the triangle KFC : Then , because the triangle AEK is equal to the triangle AHK , and the triangle KOC to KFC ; the triangle AEK , together with the triangle KGC is equal to the triangle AHK ...
... fame reafon , the triangle KGC is equal to the triangle KFC : Then , because the triangle AEK is equal to the triangle AHK , and the triangle KOC to KFC ; the triangle AEK , together with the triangle KGC is equal to the triangle AHK ...
Σελίδα 49
... fame reafon , AB and AH are in the fame ftraight line ; and because the angle DBC is e- qual to the angle FBA , each of them being a right angle , add to each the angle ABC , and the whole angle DBA is B D L E £ 4. x . 1 equal to the ...
... fame reafon , AB and AH are in the fame ftraight line ; and because the angle DBC is e- qual to the angle FBA , each of them being a right angle , add to each the angle ABC , and the whole angle DBA is B D L E £ 4. x . 1 equal to the ...
Άλλες εκδόσεις - Προβολή όλων
The First Six Books: Together with the Eleventh and Twelfth Euclid Δεν υπάρχει διαθέσιμη προεπισκόπηση - 2016 |
Συχνά εμφανιζόμενοι όροι και φράσεις
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio bifected Book XI cafe centre circle ABCD circumference cone confequently cylinder defcribed demonftrated drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fide BC fides fimilar firft firſt folid angle fome fore fphere fquare of AC ftraight line AB ftraight line BC given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs likewife oppofite parallel parallelepipeds parallelogram perpendicular plane angles prifms PROP propofition pyramid ratio of BC rectangle contained rectilineal figure right angles ſquare thefe THEOR theſe triangle ABC wherefore
Δημοφιλή αποσπάσματα
Σελίδα 472 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Σελίδα 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Σελίδα 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Σελίδα 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.
Σελίδα 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.
Σελίδα 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Σελίδα 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Σελίδα 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...
Σελίδα 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Σελίδα 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.