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When the price is any even number of shillings, if it be required to know what quantity of any thing may be bought for so much money: Annex a cypher to the money, and divide it by half the price, and the quotient will be the quantity to be purchased.

EXAMPLES.

1. How many yards of cloth, at 18s. per yard, may have for £.345?

Half the price = 9)3450 = money with a cypher annexed.

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To find the value of goods sold by particular quantities, viz. I. By the score. II. Round timber. III. By 5 score to the hundred. IV. By 112 to the hundred. V. By 6 score to the hundred. VI. By the gross. VII. By the thousand.

I. To find the value of goods sold by the score.

The price of one is given, to find the price of one score.

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If the given price be shillings and pence, or only pence, divide the given price, in pence, by 12. The quotient will be the answer in pounds, and the remainder will be so many times 1s. 8d.

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It may be remarked, that when the price is shillings and pence, the answer will be just so many pounds as there are shillings, and so many times 1s. 8d. as there are pence. If farthings are given, for d. reckon 5d. for id. 10d. and for 2d. Is. 3d.

TABLE of Aliquot Parts. 20 the Integer.

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Forty feet make a load or ton of round timber.

If the given price of a foot be shillings,

RULE.

Multiply the given price by 2, and the product will be the answer

in pounds.

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If the given price of 1 foot be pence only, or shillings and pence, divide the given price, in pence, by 6. The quotient will be the answer in pounds, and the remainder will be so many times 3s. 4d.

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If the given price of a foot be farthings only, or pence and farthings, divide the given price in farthings, by 6; then divide that quotient by 4, and this last quotient will be the answer.

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Or, suppose every shilling in the price to be 21. every penny to be 3s. 4d. and every farthing to be 10d.

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III.* To find the value of goods sold by 5 score to the hundred.

1st. If the given price be pounds and shillings, or shillings only.

RULE.

Multiply the given price in shillings, by 5, and the quotient will Be the answer in pounds.

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2d. If the given price of 1 be pence only, or shillings and pence.

RULE.

Multiply the given price, in pence, by 5; then divide that product by 12. The quotient will be pounds; and the remainder so many times 1s. 8d.

15th. If

*In Federal Money.-Remove the decimal point two places to the right for the answer.

EXAMPLES.

1. What cost 100 yards at D.2 50c. per yard?

D.2.50 X 100 =

D.250', Ans.

2. What cost 100 yards at 75c. per yard?

D. 75 x 100 = D.75', Ans. 3. What cost 100 yards at 5c. 64m per yard? D.05625 × 100 = D.5 625, Ans. 4. What cost 100 yards at 37c. 5m. per yard?

Ans. D.37 50c.

5. What cost 100 yards at 68c. 74m. per yard?

Ans. D.68 75c.

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3. If the given price of 1 be shillings and pence: Multiply the price by 5, and the product under the place of shillings, will be the answer in pounds, and the product under the place of pence, will be so many times 1s. 8d.

17th. At 2s. 5d per bushel

what cost 100 bushels ?

s. d.

2 5

5

12 1

£.12 1 8 Ans.

:

18th. At 25s. 3d. per ton: what cost 100 tons ?

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4.* To find the price of one at so much per hundred of 5 score.

GENERAL RULE.

Multiply the given price by 12; divide the product by 5, and the quotient will be the answer in pence.

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Divide the given price by 5, and the quotient will be the answer in shillings.

19th. If

*In Federal Money-Remove the decimal point two places to the left for the anfwer.

EXAMPLES.

1. If 100 yards cost D.250, what cost 1 yard?

D.250 100 D.2.50 Ans.

2. If 100 yards cost D.75', what cost 1 yard?

D.75 100 = D. 75, Ans.

3. If 100 yards cost D.5 62c. 5m, what cost 1 yard? D.5.625 100 D. 05625

=

5c. 64m. Ans.

4. If 100 yards cost D.37 50c. what cost 1 yard?

Ans. 37c. 5m.

5. If 100 yards cost D.68 75c. what cost 1 yard?

Ans. 68c. 7m.

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22d.* At 31. 7s. 6d. per 100: What will 23 cost?

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£ s d.

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23

£.0 15 6 Ans.

23d. At

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To find the value of any number at a given price per 100, in federal money.—Multiply the price per 100 by the given quantity, and point off two right hand figures, in the product more than required by multiplication of decimals. Or, point off the two right hand places in the given quantity, and multiply, and point, as in multiplication of decimals.

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100

= D.2·5025 = D.2 50c. 21m. Ans. Or, D.5·5 × 455lb. = D.2.5025, as

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Ans. D.1404 25c.

Ans. D.8 64c.

Ans. D.32.

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