EXAMPLES. 1. Reduce 17s. 8d. to the decimal of a pound. Here, in dividing 3 by 4, I suppose 2 cyphers to be annexed to the 3, which make it 3.00, and 75 is the quotient, which I write against 8 in the next line; this quotient, viz 8 75 being pence and decimal parts of a penny, I divide them by 12, which brings them to shillings and decimal parts, I therefore divide by 20, and, there being no whole number, the quotient is decimal parts of a pound. 2. Reduce 1, 2, 3, 4, and so on to 19 shillings, to decimals. Here, when the shillings are even, half the number, with a point prefixed, is their decimal expression; but if the number be odd, annex a cypher to the shillings, and then halving them, you will have their decimal expression. 3. *Reduce 1, 2, 3, and so on to 11 pence, to the decimals of a Answers. 583+, 916+. 4. Reduce 1, 2, 3, &c. to 11 pence, to the decimals of a pound. Pence. 9 -75, 10 11 •833+, 8 9 Pence. 6 7 Answers. 025, 02916+, 0333+, 0375, 0416+, 5. Reduce 1, 2 and 3 farthings to the decimals of a penny. Iqr.=25d 2qr.='5d. and 3qr=75d. Answers. 6. Reduce 1, 2 and 3 farthings to the decimals of a shilling. Answers. 1qr.=02083+s. 2qrs='04166+s. 3qrs. 0625s. 7. Reduce 1, 2 and 3 farthings to the decimals of a pound Ans. 1qr0010416+£. 2qrs 002088+. 3qrs.=.003125£. 8. Reduce 15s. 54d. to the decimal of a pound. Ans. 6729+. 9. Reduce 7Cwt. 3qrs. 17lb. 10oz. 12dr. to the decimal of a ton. Ans. 39538+. 10. Reduce 10oz. 13pwt. 9gr. to the decimal of a pound Troy. 11. Reduce 3qrs. 3n to the decimal of a yard. 12. Reduce 5fur. 12po. to the decimal of a mile. 13. Reduce 55m. 37 sec. to the decimal of a day. Ans. 8890625. Ans. 9375. Ans 6625. Ans. 03862+. ✦ The answers to this question are the fame as the decimal parts of a foot. CASE dition. for carrying from one denomination to another as in Compound Ad In the last example, I say, 9 times 1 is 9 farthings=24d. I set down and carry 2, saying, 9 times 8 is 72, and 2 I carry makes 74 pence, =6s. 2d. I set down 2 in the pence and carry 6; then, 9 times 7 (the unit figure in the shillings) is 63, and 6 I carry is 69, I set down 9 under the unit figure of the shillings, and carry 6, saying, 9 times 1 is 9, and 6 I carry is 15, then I halve 15, which is 7 and I over, which I set in the ten's place in the shillings, and that, with the 9, makes 19 shillings; then I carry the 7 as pounds: Lastly, 9 times 4 is 36, and 7 I carry, are 43 pounds: I set down 3 and carry 4, saying, 9 times 1 is 9, and 4 I carry makes 13, which I set down, and the product is .133 19s. 2d. PRACTICAL QUESTIONS. Note. The facility of reckoning in the Federal money, compared with pounds, shillings, &c. may be seen from the examples in this and the following cases; where the same questions are given in both the currencies, as near as can be, avoiding small fractions. It may be observed, that the variety of cases here given is applicable only to the old currency, while the same questions in the Federal are solved by plain decimals. 1. What will 9 yards of cloth at 5.9m. Multiplied by d{ } per yard, come 88c. .0 5s. 4d. price of one yard, 88c. 9m. Ans. .280 price of 9 yds. D. 8 00 1 :{ 15s. 4d. 2D. 55c. 6m. to } 4.9 When the multiplier, that is, the quantity, is above 12: You must multiply by two such numbers, as, when multiplied together, will produce the given quantity. EXAMPLES. When the quantity is such a number, as that no two numbers in the table will produce it, exactly: Then multiply by two such numbers as come the nearest to it; and for the number wanting, multiply the given price of one yard by the said number of yards wanting, and add the products together for the answer; but if the product of the two numbers exceed the given quantity, then find the value of the overplus, which subtract from the last product, and the remainder will be the answer. EXAMPLES. 1. What will 47 yards of cloth, at come to ? 17s. 9d. } per yard, £. s. d. Produces 39 18 9 price of 45 yards. Ans. D.139-026 Add 1 15 6 price of 2 yards. Ans. .41 14 3 price of 47 yards. Note. Note. This may be performed by first finding the value of 48 yards, from which if you subtract the price of 1, the remainder will be the When the quantity is any number above the Multiplication Table: Multiply the price of 1 yard by 10, which will produce the price of 10 yards: This product, multiplied by 10, will give the price of 100 yards; then, you must multiply the price of one hundred by the number of hundreds in your question; the price of ten, by the number of tens; and the price of unity, or 1, by the number of units: Lastly, add these several products together, and the sum will be the answer. EXAMPLES. 1. What will 359 yards of cloth, at 4s. 7d. to? {77c. 71 m. } per yard, amount £. s. d. c. m. 0 4 7 price of 1 yard. •771 359 CASE V. To find the value of one hundred weight: As 112 is the gross hundred, so 112 farthings are 2s. 4d. and 112 peńce 9s. 4d. ; therefore, if the price be farthings, or not more than 3d. multiply 2s. 4d. by the farthings in the price of 1 lb or, if the price be pence, multiply 9s. 4d. by the pence in the price of 1 lb. and in either case, the product will be the answer. EXAMPLES. 1. What will 1 Cwt. of chalk come to at :{ lid. 2c. 1m. 112 farthings= 0 2 4 price of 1 Cwt. at 4 per lb. 6 farthings in the price. lid. = Answer .0 14 O price of 1 Cwt. at 11⁄2 per lb. } per pound? ⚫021 112 s. d. 42 21 21 Ans. 2.352 2. 1Cwt of tin at 24d. per lb.? 2 4 price of 1 Cwt. at d. per lb. 9 farthings in the price of 1 lb. ⚫03125 Ans. D.3.50000 3. 1 Cwt. of lead at ⚫098 112 196 98 98 {9c.8m. Ib. 29 4 price of 1 Cwt. at 1d. per lb. 7 pence in the price of 1 lb. £.3 5 4 price of 1 Cwt. at 7d. per lb. To find the value of two, or more hundreds, by having the price of one pound: First, find the price of 1 Cwt. by the last Case, and then proceed to find the value of the whole by Case 1st. or 2d. as the ques-tion may require. EXAMPLES. |