 | John Davidson, Robert Scott (writing master) - 1818 - 190 σελίδες
...the divisor. The tum of these three parts will be the complete divisor, which multiply by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next part for a new dividend. Proceed in the same manner as before to find the divisor... | |
 | John Radford Young - 1832 - 408 σελίδες
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term of the root, subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. For (by Art. 37), the cube of a + b is a3 + 3a2¿... | |
 | Benjamin Peirce - 1837 - 300 σελίδες
...is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
 | Benjamin Peirce - 1837 - 302 σελίδες
...is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
 | John Radford Young - 1839 - 332 σελίδες
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term of the root, subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. For (by Art. 37,) the cube of a+b is a»+ 3a2¿>... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 σελίδες
...right ; add together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under the complete... | |
 | George Roberts Perkins - 1841 - 274 σελίδες
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
 | James Bates Thomson - 1846 - 402 σελίδες
...the root, also on the right of the partial divisor ; multiply the divisor thus completed by the last figure of the root ; subtract the product from. the dividend, and to the remainder bring down the next period for a new dividend, as before. IV. Double the root already found for a new... | |
 | James Bates Thomson - 1846 - 354 σελίδες
...the root, also on the right of the partial divisor ; multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, as before. IV. Double the root already found for a new... | |
 | James Bates Thomson - 1847 - 426 σελίδες
...the right of the partial divisor ; multijily the divisor thus completed b;/ the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial... | |
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This sum will be the complete divisor. Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next group for a new dividend. 
