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Βιβλία Βιβλία 1 - 10 από 20 για The rectangle of the radius, and sine of the middle part, is equal to the rectangle....
" The rectangle of the radius, and sine of the middle part, is equal to the rectangle of the tangents of the two EXTREMES CONJUNCT, and to that of the cosines of the two EXTREMES DISJUNCT. "
Trigonometry, Plane and Spherical: With the Construction and Application of ... - Σελίδα 34
των Thomas Simpson - 1810 - 125 σελίδες
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Principles of Education, Intellectual, Moral, and Physical

Lant Carpenter - 1820 - 477 σελίδες
...of right-angled spherical triangles. Here the short sentence, " the rectangle of the radius and the sine of the middle part, is equal to the rectangle of the tangents of the extremes conjunct, or, of the cosines of the extremes disjunct," enables the calculator...

American Practical Navigator

1821
...'„_ These equations, when applied to-right-angled spheric triangles, signify as before thtit the sine of the middle part is equal to the rectangle of the tangents of the adjacent parts, or to the rectangle of the co-sines of the opposite parts ; but when...

A treatise on navigation, and nautical astronomy

Edward Riddle - 1824 - 551 σελίδες
...solution of the different cases of right angled spherical triangles are 1. The rectangle of radius and the sine of the middle part is equal to the rectangle of the tangents of the adjoining extremes. 2. The rectangle of radius and the sine of the middle part is equal...

The New American Practical Navigator: Being an Epitome of Navigation ...

Nathaniel Bowditch - 1826 - 617 σελίδες
...П1Ш< „art These equations, when applied to right-angled spheric triangles, signify as that the sine of the middle part is equal to the rectangle of the tangents of the ¡ parts, or to the rectangle of the co-sines of the opposite parts ; but when appui...

The New American Practical Navigator: Being an Epitome of Navigation ...

Nathaniel Bowditch - 1826 - 617 σελίδες
..., ''These equations, when applied to right-angled «phenc triangles, signify as before, H. that the sine of the middle part is equal to the rectangle of the tangents of the adjacent parts, 01 to the rectangle of the co-eiiies of the opposite parts : but when...

A London Encyclopaedia, Or Universal Dictionary of Science, Art ..., Τόμος 22

Thomas Curtis - 1829
...С opposite extremes. With these explanations Napier's rules are 1. The rectangle of radius and the sine of the middle part is equal to the rectangle of the tangents of the adjoining extremes. 2. The rectangle of radius and the sine of the middle part is equal...

Elements of Geometry and Trigonometry

Adrien Marie Legendre - 1836 - 359 σελίδες
...triangles, which it must be remembered apply to the circular parts, as already defined. 1st. Radius into the sine of the middle part is equal to the rectangle of the tangents of the adjacent parts. 2d. Radius into the sine of the middle part is equal to the rectangle...

Elements of Trigonometry, Plane and Spherical: Adapted to the Present State ...

Charles William Hackley - 1838 - 307 σελίδες
...middle part is equal to the rectangle of the tangents of the adjacent parts. 2. Radius multiplied by the sine of the middle part is equal to the rectangle of the cosines of the opposite parts. Or both rules may be given thus : radius into the sine of the middle part = the rectangle of...

Elements of Trigonometry, Plane and Spherical: Adapted to the Present State ...

Charles William Hackley - 1838 - 307 σελίδες
...angled triangle may be expressed in the two following rules of Napier : 1. Radius multiplied by the sine of the middle part is equal to the rectangle of the tangents of the adjacent parts. 2. Radius multiplied by the sine of the middle part is equal to the...

A Treatise on Plane and Spherical Trigonometry: Including the Construction ...

Enoch Lewis - 1844 - 228 σελίδες
...the sine of the middle part is equal to the rectangle of the tangents of the adjacent extremes. 99 part is equal to the rectangle of the cosines of the opposite extremes. These rules may be explained and demonstrated in the following manner : c Let ABC be the triangle,...




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