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Βιβλία Βιβλία 1 - 10 από 180 για of $29600 = $3700, the required number. From these solutions we obtain the following....
" of $29600 = $3700, the required number. From these solutions we obtain the following rule for finding a number when a decimal part of it is given : 503. RULE.—Move the decimal point as many places to the right as there are places in the given decimal,... "
A Complete Arithmetic: Oral and Written - Σελίδα 95
των Malcolm MacVicar - 1879 - 394 σελίδες
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New system of commercial arithmetic

Robert Murray (schoolmaster.) - 1830
...vulgar fractions. When the multiplier is 10, 100, 1000, &c. the operation is performed by removing the decimal point as many places to the right as there are ciphers in the multiplier. The reason is, multiplying by 10, 100, 1000, &c. is performed by annexing...

The elements of arithmetic

Augustus De Morgan - 1830
...instances we get the following rule:—To multiply a decimal fraction by a decimal number (106), move the decimal point as many places to the right as there are ciphers in the decimal number. When this cannot be done, add ciphers to the right of the decimal (116)...

A Complete System of Commercial Arithmetic, Its Application to the Principal ...

William Tate - 1837 - 337 σελίδες
...cancelling the decimal point in the divisor, and correcting the dividend by removing the decimal point so many places to the right, as there are places in the given divisor.* EXAMPLE 1. To divide £ 3764 by 10, by 100, and by 1000. £ 3.764 0.3764 0.03764 To divide...

The Elements of Arithmetic...

Augustus De Morgan - 1840 - 162 σελίδες
...instances we get the following rule:—To multiply a decimal fraction by a decimal number (126), move the decimal point as many places to the right as there are ciphers in the decimal number. When this cannot be done, add ciphers to the right of the decimal (137)...

A New System of Arithmetic: In which is Explained and Applied to Practical ...

Calvin Tracy - 1840 - 311 σελίδες
....0625, or 6J cts. Note.—To multiply a decimal by 10, 100, 1000, &c., it is necessary only to remove the decimal point as many places to the right as there are cyphers in the multiplier. 13. Multiply 1.56 by 10. Ans. 15.6. 14. Multiply 36.541 by 100. Ans. 3654.1....

The Elements of Arithmetic

Augustus De Morgan - 1840 - 166 σελίδες
...instances we get the following rule: — To multiply a decimal fraction by a decimal number (126), move the decimal point as many places to the right as there are ciphers in the decimal number. When this cannot be done, add ciphers to the right of the decimal (137)...

A New System of Arithmetic: In which is Explained and Applied to Practical ...

Calvin Tracy - 1842 - 288 σελίδες
....0625, or 6£ cts. NOTE. — To multiply a decimal by 10, 100, 1000, &c., it is necessary only to remove the decimal point as many places to the right as there are ciphers in the multiplier. 13. Multiply 1.56 by 10. Ans. 15.6. 14. Multiply 36.541 by 100. .Ans. 3654.1....

The principles of arithmetic. [Followed by] The principles of algebra

Wales Christopher Hotson - 1842
...fractions being The multiplication of a decimal by a number of the form 1000... is performed by removing the decimal point as many places to the right as there are ciphers in the multiplier; for the local values of the figures increase ten -fold for every place the...

The Elements of Arithmetic ... in which Decimal and Integral Arithmetic are ...

Pliny Earle Chase - 1844
...other factor. The product by zero is always zero. To multiply any number by 10, 100, 1000, &c., remote the decimal point as many places to the right, as there are zeroes in the multiplier. When there are zeroes at the right hand of either, or both factors, perform...

Elements of Arithmetic: For Schools and Academies. In which Decimal ..., Μέρος 2

Pliny Earle Chase - 1844 - 240 σελίδες
...other factor. The product by zero is always zero. To multiply any number by 10, 100, 1000, die., remove the decimal point as many places to the right, as there are zeroes in the multiplier. When there are zeroes at the right hand of either, or both factors, perform...




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