 | John Bonnycastle - 1813 - 456 σελίδες
...next term of the root. Involve the whole of the root, thus found, to its proper power, which subtract from the given quantity, and divide the first term of the remainder by the same divisor as before; and proceed in this manner, till the whole is finished (л1). - (т) As... | |
 | Jeremiah Day - 1814 - 304 σελίδες
...next, Sic. Take the root of the first term, for the first term of the required root: Subtract the power from the given quantity, and divide the first term of the remainder, by the first term of the root involved to the next inferiour power, and multiplied by the index of the... | |
 | John Bonnycastle - 1818 - 284 σελίδες
...next term of the root * Involve the whole of the root, thus found, to its proper power, which subtract from the given quantity, and divide the first term of the remainder by the same divisor as before ; and proceed in this manner tilt the whole is finished. (;,) * EXAMPLES.... | |
 | James Ryan, Robert Adrain - 1824 - 542 σελίδες
...next term of the root. Involve the whole of the root, thus found, to its proper power, which subtract from the given quantity, and divide the first term of the remainder by the same divisor as before. Proceed in the same manner, for the next following term of the root ; and... | |
 | James Ryan - 1824 - 550 σελίδες
...next term of the root. Involve the whole of the root, thus found, to its proper power, which subtract from the given quantity, and divide the first term of the remainder by the same divisor as before. Proceed in the same manner, for the next following term of the root ; and... | |
 | John Bonnycastle - 1825 - 336 σελίδες
...next term of the root. Involve the whole of the root, thus found, to its proper power, which subtract from the given quantity, and divide the first term of the remainder by the same divisor as before ; and proceed in this manner till the whole is finished*. « As this rule,... | |
 | Jeremiah Day - 1827 - 352 σελίδες
...next, &c. Take the root of the first term, for the first term of the required root : Subtract the power from the given quantity, and divide the first term of the remainder, by the first term of the root involved to the next inferior power, and multiplied by the index of the... | |
 | John Bayley (fellow of Emmanuel College, Cambridge.) - 1830 - 428 σελίδες
...term in the root; subtract * * * * the cube of the root thus found from the given quantity. Again, divide the first term of the remainder by 3 times...before, and the quotient is the third term in the root. EXAMPLE. Find the cube root of a2 + 3агс + Васг + с2 + 3a*d + 6acd + Bсd2 + 3ad* + 3cd2 +... | |
 | Charles Davies - 1835 - 378 σελίδες
...of R. If then, we form the cube of the two terms of the root already found, and subtract it from N, and divide the first term of the remainder by 3 times the square of the first term of R, the quotient will be the third term of the root. Therefore, having arranged the terms of JV,... | |
 | 1836 - 488 σελίδες
...quantities, take the root of the first term, for the first term of the required root. Subtract the power from the given quantity, and divide the first term of the remainder by the first term of the root, involved to the next inferior power, and multiplied by the index of the... | |
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Subtract the power from the given quantity, and divide the first term of the remainder by the... 
