The first six books of the Elements of Euclid, with numerous exercises |
Αναζήτηση στο βιβλίο
Αποτελέσματα 1 - 5 από τα 34.
Σελίδα 15
Again , because the exterior angle of a triangle is greater than the interior and opposite angle , the exterior angle bdc of the triangle cde is greater than ced ; for the same reason , the exterior angle ceb of the triangle a be is ...
Again , because the exterior angle of a triangle is greater than the interior and opposite angle , the exterior angle bdc of the triangle cde is greater than ced ; for the same reason , the exterior angle ceb of the triangle a be is ...
Σελίδα 24
... be not terminated in the same point d ; then , because a b c d is a parallelogram , ad is equal ( i . 34 ) to bc ; b for the same reason e f is equal to & bc ; wherefore a d is equal ( 1 ax 24 THE ELEMENTS OF EUCLID .
... be not terminated in the same point d ; then , because a b c d is a parallelogram , ad is equal ( i . 34 ) to bc ; b for the same reason e f is equal to & bc ; wherefore a d is equal ( 1 ax 24 THE ELEMENTS OF EUCLID .
Σελίδα 25
For the like reason , the parallelogram efgh is equal to the same ebch . Therefore also the parallelogram abcd is equal to efgh . Wherefore parallelograms , & c . Q. E. D. C 160 PROPOSITION XXXVII . — THEOREM .
For the like reason , the parallelogram efgh is equal to the same ebch . Therefore also the parallelogram abcd is equal to efgh . Wherefore parallelograms , & c . Q. E. D. C 160 PROPOSITION XXXVII . — THEOREM .
Σελίδα 29
34 ) to the triangle adc : and , because ekha is a parallelogram , the diameter of which is a k , the triangle a e k is equal to the triangle a hk : for the same reason , the triangle kgc is equal to the triangle kfc .
34 ) to the triangle adc : and , because ekha is a parallelogram , the diameter of which is a k , the triangle a e k is equal to the triangle a hk : for the same reason , the triangle kgc is equal to the triangle kfc .
Σελίδα 31
14 ) with a g ; for the same reason , a b and a h are in the same straight line ; and because the angle dbc is equal to the angle f ba , each of them being a right angle , add to each the angle a b c , and the whole angle dba is equal ...
14 ) with a g ; for the same reason , a b and a h are in the same straight line ; and because the angle dbc is equal to the angle f ba , each of them being a right angle , add to each the angle a b c , and the whole angle dba is equal ...
Τι λένε οι χρήστες - Σύνταξη κριτικής
Δεν εντοπίσαμε κριτικές στις συνήθεις τοποθεσίες.
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
a b c angle a b c angle bac base base bc bc is equal bisected centre circle circumference common compounded definition demonstrated describe diameter divided double draw equal angles equal to f equiangular equilateral equimultiples exterior angle extremity fall fore four fourth given straight line greater half ILLUSTRATED inscribe join less likewise magnitudes manner meet multiple parallel parallelogram pass perpendicular produced proportionals PROPOSITION ratio reason rectangle contained rectilineal figure remaining angle right angles segment shewn sides similar square square of a c straight line a b Take taken third touches the circle triangle triangle a b c wherefore whole