 | 1801 - 446 σελίδες
...by the number of parts in the next less denomination, and cut off as many places for a remainder on the right hand, as there are places in the given decimal....parts in the next inferior denomination, and cut off for a remainder, as before. ' 3. Proceed in this manner through all the parts of the integer, and the... | |
 | Nicolas Pike - 1802 - 350 σελίδες
...the decimal by the number of -parts in the next lefs denomination, and cut oft fo many places for a remainder, to the right hand, as there are places...the given decimal. 2. Multiply the remainder by the next jnferior denomination, and cut off a remainder as before.. 3. Proceed in this manner through all... | |
 | James Thompson - 1805 - 100 σελίδες
...fraction by the number or parts :in the next lower denominator; and point off as many places for a remainder, to the right hand, as there are places in the given decimal fraction. Multiply that remainder by the number of parts in the next lower denomination again, pointing... | |
 | Nicolas Pike - 1807 - 370 σελίδες
...the decimal by the number of parts in the next lefs denomination, and cut off fo many places for a remainder, to the right hand, as there are places...the given decimal. 2. Multiply the remainder by the next inferiour denomination, and cut off a remainder as before. 3. Proceed in this manner through all... | |
 | Samuel Webber - 1808 - 466 σελίδες
...part, irill be an exact decimal expression for them. Whence, if the V0L. I. L t mainder on the right as there are places in the given decimal. 2. Multiply...parts in the next inferior denomination, and cut off for a remainder as before. 3. Proceed in this manner through all the parts of the integer, and the... | |
 | Samuel Webber - 1812 - 260 σελίδες
...number of parts in the next less denomination, and cut off as many places for a remainder on the right as there are places in the given decimal. 2. Multiply...parts in the next inferior denomination, and cut off for a remainder as before. 3. Proceed in this manner through all the parts of the integer, and the... | |
 | Nathan Daboll - 1813 - 244 σελίδες
...number of parts in the next CM denomination, and cut oft* so many places for a remainder, to illriglit hand, as there are places in the given decimal. 2. Multiply the remainder by the next inferior denomination, and cut off a remainder as before ; and so on through all the parts of... | |
 | Nathan Daboll - 1815 - 250 σελίδες
...by the number of parts in the next less denomination, and cut off so many places for a remainder, ti the right hand, as there are places in the given decimal. 2. Multiply the remainder by tite pest inferior denom. ination, and cut oft' a remainder as before; and so on through all the parts... | |
 | Charles Hutton - 1816 - 610 σελίδες
...the decimal by the number of parts in the next lower denomination ; and cut off as many places for a remainder to the right hand, as there are places in the given decimal Multiply lhat remainder by the parts in the next lower denomination again, cutting off lor another... | |
 | Nathan Daboll - 1817 - 252 σελίδες
...the decimal by the number of parts in the next less denomination, and cut off so many places for a remainder, to the right hand, as there are places...the given decimal. 2. Multiply the remainder by the next inferior denomination, and cut off a remainder as before ; and so on through all the parts of... | |
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Multiply the decimal by the number of parts in the next less denomination, and cut off so many places for a remainder, to the right hand, as there are places in the given decimal. 2. Multiply the remainder by the next inferior denomination, and cut off... 
