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eonts will he receive at that rate for 17 days? For 29 days? #11776 cents. For 116 days? For 105 days? A. 56576.

In

6. If the stage run 9 miles an hour, how many miles will it Pun at that rate in 12 nours? In 19 hours? A. 279 miles. 25 hours? In 36 hours? A. 549 miles.

9. If a man save 161 dollars in a year, how much will it amount to in 19 years? In 35 years? A. 8694 dollars.

10. Multiply 62123 by 13.

11. Multiply 35432 by 14; by 15.
12. Multiply 65217 by 16; by 17.
13. Multiply 207812 by 19; by 21.
14. Multiply 207812 by 25; by 35.
15. Multiply 32100421 by 65; by 85.
16. Multiply 32100421 by 27; by 33.

A. 807599.
A. 1027528

A. 2152161.
A. 8312480.
A. 12468720.
A. 4815063150
A. 1926025460

17. Write down one thousand, multiply it by 25, add five thousand to the product, subtract twenty-nine thousand nine hundred and ninety-nine from the amount, and see if the re mainder be 1.

↑ XII.

When the Multiplier is 10, 100, 1000, &c.

How many are 10 times 5? Now, if we annex a cipher to the 5, thus, 50, it will produce the same effect: why is this? A. Because, by annexing a cipher to 5, the 5 is removed to the tens' place; hence the value is increased 10 times.

What effect would two ciphers have, or three ciphers, &c.? A. Two ciphers would remove any figure two places towards the left, and of course increase it 100 times, and so on for 1000, &c.

RULE. What, then, appears to be the rule? A. Annex to the multiplicand all the ciphers in the multiplier.

Exercises for the Slate.

1. What will 36 bushels of rye cost, at 100 cents a bushel? A. 3600 cents.

2. What will 100 bushels of salt cost, at 87 cents a bushel? What will 1000 bushels? What will 10000 bushels? What will 10 bushels? A. 966570 cents.

3. Multiply 8978 by 10; by 100; by 1000; by 10000; by 100000; by 1000000. A. 9975545580.

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1 XIII. When there are ciphers at the right hand of either or both the Factors.

RULE. From the illustrations given, TXII., how does it apperr that we can multiply? A. Multiply without the ciphers first, and annex them to the product.

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TXIV. When the Multiplier is a Composite Number.

How many are 5 times 8? 7 times 9? 12 times 12? What are these products, 40, 63, 144, called? A. Composite Numbers.

What are the multiplying numbers, 5 and 8, 7 and 9, 12 and 12, called? A. The Component Parts.

What are the component parts of 36? Of 72? Of 100? Of 27? Of 15? Of 35 Of 132? Of 144?

What, then, is the product of any two numbers called? A A Composite Number.

1. What will 14 barrels of flour cost, at 8 dollars a barrel?

OPERATION.

8 dollars.

7 barrels.

56 dollars.

2 times 7 are 14.

112 dollars, Ans.

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RULE I. How, then, would you begin to multiply? A. By one of the component parts first.

II. What would you multiply this product vyŶ A. By the other component part.

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More Exercises for the Slate.

2. What will 36 hundred weight of sugar cost, at 29 dellars

a hundred? A. 1044 dollars.

3. Multiply 3065428 by 35.

4. Multiply 4078945 by 96.
5. Multiply 18934 by 108.

6. Multiply 45679 by 144.

SIMPLE DIVISION.

A. 107289980.

A. 391578720.

A. 2044872.

A. 6577632.

XV. 1 If you divide 12 apples equally between two boys, how many will each have? How many times 2 in 12, then? Why? A. Because 2 times 6 are 12.

2. How many oranges, at 8 cents apiece, can you buy for 48 cents? For 96 cents? How many times 8 in 48? 8 in 96? Why?

3. A man bought 8 lemons for 80 cents; how much did he give apiece? How many times 8 in 80 ? Why, or proof? 4. How many gallons of brandy, at 3 dollars a gallon, can be bought for 36 dollars? For 60 dollars › For 90 dollars? For 300 dollars? Why?

5. Four boys found a bag containing 48 silver dollars; how many will they have apiece, if it be divided equally?

6. When oranges are 2 cents apiece, how many will 8 cents buy? Will 16 cents buy? Will 32 cents? Will 36 cents? Wil: 48 cents? Will 100 cents?

7. If you pay 9 cents for one pound of sugar, how many pounds can you buy for 45 cents? For 54 cents? For 103

cents?

8. How much is one half (2) of 4? Of8? Of 16? Of 20? Of 24? Of 30? Of 100? Of 200?

9. Harry had 16 apples, and gave one half () of them to Thomas; how many did Thomas receive?

10. How much is one third (3) of 6? Of 24? Of 30? Of 36 ?

11. How much is one half () of 8? One third (}) of 24 ? One fourth (1) of 16? One fifth () of 35? One sixth (†) of 24? One seventh (4) cf 35? One eighth (4) of 56? One ninth () of 108? One twelfth (TZ) of 144?

12. How many times 4 in 40? 1200? 8 in 480?

3 in 60? 5 in 100? 6 in

Q. What is this method of finding how many times one num ber is contained in another, or of dividing a number into equal parts, called? A. Division.

Q. What is the method of finding how many times one num her is contained in another of only one name, or denomination, called. A. Simple Division.

Q. What is the number given to divide by called? A. The Divisor.

Q. What is the number to be divided called? A. The Dividend.

Q. What is the number of times that the divisor is contained in the dividend called? A. The Quotient.

Q. What is that which is sometimes left after diriding, or after the operation is performed, called? A. The Remainder, which must always be less than the Divisor.

Q. Of what name, or denomination, is the remainder? A. The same as the dividend.

Q. If your dividend, for instance, be ounces, what will your remainder be? A. Ounces.

Q. How many times 4 in 40? and why?

Q. From this example what does division appear to be the opposite of? A. Multiplication.

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3d time he had

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2nd time he had

Q. James, having 12 oranges, was desirous of dividing them equally among his 4 little sisters, and, in order to do this, he handed them at first one apiece; how many had left?

Q. When he handed them another apiece, how many had he left?

Q. When he handed them one more apiece, how many had he left?

Q. From these illustrations how does it appear that a num ber may be divided into equal parts? A. By Subtraction.

Q. How many times did James give to each of his sisters an orange apiece?

Q. How many times did you subtract? A. Three times. Q. How many times 4 in 12?

Q. By this we see that the quotient represents the number of subtractions: now, if the quotient were 4000, how many times would it be necessary to take the divisor from the dividend to perform division by subtraction A. 4000 times.

Q. What, then, is Invisi a quick way of performing? A. Many subtractions.

SHORT DIVISION.

↑ XVI. Q. What is SHORT DIVISION? A. When the divisor is 12, or less.

1. How many oranges, at 3 cents apiece, may be bought for 657 cents?

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OPERATION.
Dividend.

Divisor, 3)657 cents.

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How do you obtain the 2 (hundreds) in the quotient? A. I begin on the left of the dividend, and say, 3, the divisor, is contained in (hundreds) 2 (hundreds) times, that is, 200 times, writing the 2 (hundreds) down under the 6 (hundreds). How do you get the 1 (ten)? A. 3 in 5 (tens) I time, and 2 (tens) left.

Quotient, 219 oranges, Ans.

6

What do you do with the 2 which is left? A. I join, or carry it as 2 tens, that is, 20 units, to the 7 units, making 27. How do you proceed to get the 9, then? A. 3 in 27, 9 times.

PROOF.

Quotient, 219
Divisor,

3

Dividend, 657

How many times 6 in 30? and why? How, then, would you proceed to prove the foregoing example? A. I would multiply 219 (the quotient) by 3 (the divisor), making 657 (the dividerd)-therefore right.

From the illustrations now given we derive the following

RULE.

1. At which hand of the dividend do you place the divisor? A At the left.

II How many figures do you take first? A. Enough to contain the divisor once, or more.

III What do you set down underneath? A. The quotient. IV. If there should be a remainder, how would you pro ceed A. I join, or carry it to the next figure of the dividend, as so many tens. For example, suppose 3 remain, and the next figure be, how would you say? A. I would say, 3 (to carry) to 8, makes 3.

V. How do you proceed if the divisor be not contained in the nert figure of the dividend A. Write a cipher in the quo tient, and join this figure to the figure next to it, as so many

tens.

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