3. In 999888 mills, how many dollars, cents and mills? 99918818 Ans. $999.88.8. 7. In 8828 lbs. Avoirdupois Weight, how many tons? Ans. 3 tons. 18cwt. 3qrs. 8lbs. 8. In 524 lbs. Avoirdupois Weight, how many cwt. Ans. 4 cwt. 2 qrs. 20lbs. 9. In 253440 grains, Troy Weight, how many lbs? &c. Ans. 44. 10. In 155520 grains, Apothecaries Weight, how many pounds? Ans: 27. 11. How many miles are there in 1,585,267,200 inches? Ans. 25020. 12. In 4000 nails, how many yards? Ans. 250. 13. In 8000 square rods, how many acres? 14. In 2016 pints of wine, how many tuns? 15. How many bushels are there in 80,000 quarts? Ans. 50. Ans. 1. Ans, 2500. 16. In 2,522,880,000 seconds, how many days? Ans. 29,200. 17. In 3840 solid feet, how many cords? 19. Bring 240,000 pence to pounds. Ans. 2. Ans. £1000. Ans. 28 cwt. Ans. 40L, Ans. 32 fur. Ans. 240 qrs. 24. Reduce 17280 cubick, or solid inches, to solid feet. Ans. 10 solid feet. 25. In 768 pints, how many bushels? Ans. 12. 26. In 1890 gallons, how many hogsheads? Ans. 30. 2. By what rules are its operations performed? 4. What is your rule for Reduction Descending? 8. How is Reduction proved? 56 COMPOUND ADDITION. Compound Addition teaches to add numbers which represent articles of different value, as pounds, shillings, pence; or yards, feet, inches, &c. called different denominations. The operations are to be regulated by the value of the articles, which must be learned from the foregoing table. RULE. Place the numbers to be added so that those of the same denomination may stand directly under each other. Add the figures of the first column or denomination together, and divide the amount by the number which it takes of this denomination to make one of the next higher. Set down the remainder, and carry the quotient to the next denomination. Find the sum of the next column or denomination, and proceed as before through the whole, until you come to the last column, which must be added by carrying one for every ten as in Simple Addition. In the first of the above examples, I begin with the right hand column, or that of farthings; and having added it, find that it contains 6. Now, as 6 farthings contain 1 penny and 2 over, I set the 2 farthings, under the column of farthings, and carry the penny to the column of pence. In the column of pence I find 29, which, with the one carried from the farthings, make 30. In 30 pence I find there are 2 shillings and 6 pence over: setting the 6 pence under the column of pence, I add the 2 shillings to the column of shillings. In this column are 29, and the 2 added make 31. Thirtyy-one shillings contain 1 pound, and 11 shillings over. The 11 shillings are then placed under the column of shillings, and the 1 is carried to the column of pounds. In that column are 33 pounds, which, with the 1 added, make 34. Thus the amount of the sum is 34 pounds, 11 shillings, 6 pence, and 2 farthings. In all cases in Compound Addition, one must be carried for the number of times that the higher denomination is contained in the column of the lower denomination. Thus, in Troy Weight: as 24 grains make one pennyweight, one from the column of grains is carried for every 24; in the column of pennyweights, one for every 20; and in every instance the learner must be guided by the foregoing table of "Money, Weights, Measures, &c." Note. Sums in Compound Addition may be proved in the same manner as in Simple Addition. |