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ADDITION OF DENOMINATE NUMBERS.

82. IF we wish to find the sum of £6 5s. 3d. 1 far £7 1s. 10d. 2 far., £1 13s. 5d., £4 18s. Od. 2 far., we pro ceed as follows:

OPERATION.

£ s. d. far.

6

5

3

1

0

2

7 1

1 13 5 0

4 18 0 2

£19 18s. 7d. 1 far.

Placing the numbers of the same denomination directly under each other, we add up the column of farthings, which we find to be 5. But we know that 5 farthings are equivalent to 1 penny and 1 farthing; we therefore write down the 1 farthing under the column of farthings, and carry the penny into the next column, whose sum thus becomes 19 pence, which is the same as 1 shilling and 7 pence; we write down the 7 pence under the coiumn of pence, and carry the shilling to the column of shillings; whose sum then becomes 38 shillings, which is the same as 1 pound and 18 shillings; we write down the 18 shillings under the column of shillings, and carry the pound into the column of pounds, whose sum then becomes 19 pounds; and since pounds is the highest denomination, we write down the whole.

From this example we may deduce this general

RULE.

I. Place the numbers so that those of the same donomina tron may stand directly under each other, and draw a line beneath them.

II. Add the numbers in the lowest denomination, divide their sum by the number expressing how many it takes of such denomination to make one of the next higher Write

the remainder under the column added, and carry the quotient to the next column; which add as before.

III. Proceed thus through all the denominations to the highest, whose sum must be set down entire.

How do you place denominate numbers which are to be added? Which do you first add? Having added the column of lowest denominations, explain the subsequent work

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63. IF we wish to subtract £15 13s. 10d. from £20 5s. 8d., we proceed as follows:

OPERATION.

£ S. d. 20 5 8 15 13 10

4 11 10

We place the numbers of the subtrahend directly under the numbers of the same denomination in the minuend, and draw a line underneath. Commencing with the pence, we see that we cannot subtract 10d. from 8d.; we therefore increase the 8d. by 12d. making 20d.; then subtracting 10d. from the 20d., we have the difference 10d., which we write under the column of pence. Having added 12d. to the minuend, we must equally increase the subtrahend, which we do by

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