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Βιβλία Βιβλία 1 - 10 από 59 για RULE. Divide the given interest by the interest of the given principal, for the given....
" RULE. Divide the given interest by the interest of the given principal, for the given time, at 1 per cent. EXAMPLES. 1. "
An Elementary Arithmetic Designed for Academies and Schools: Also Serving as ... - Σελίδα 256
των George Roberts Perkins - 1855 - 347 σελίδες
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The Youth's Assistant in Theoretic[!] and Practical Arithmetic ...

Zadock Thompson - 1832 - 168 σελίδες
...the answer. Therefore, ... j \ I V. The principal, rate and interest being given, tofind the time. RULE.— Divide the given interest by the interest of the given principal for 1 year at the given rale, and the quotient will be the time m years and decimal parts. 2. If the mterest...

The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - 1832 - 168 σελίδες
...answer. Therefore, -• - IV. The principal, rate and interest being gtven, to fjidt!wtim$, ROLE. — Divide the given interest by the interest of the given principal for 1 year at the given rate, and the quotient will be the time in years and decimal parts. 2. If the interest...

A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - 1837 - 256 σελίδες
...ratio of the interest for 1 year is to the given interest as 1 year is to the time required. Hence the RULE : DIVIDE the given interest by the interest of the given principal for 1 year, and the quotient will be the answer. 2. In what time will $240 gain $4,80, at 6 per cent? Answer,...

A New System of Arithmetic: In which is Explained and Applied to Practical ...

Calvin Tracy - 1840 - 311 σελίδες
...8 months 1 Ans. $360. Prob. 37. Given the principal, interest, and time, to find the rate per cent. RULE. — Divide the given interest by the interest of the given principal, at one per cent, for the given time. Ex. 1. A man having $4000 on interest, at the expiration of one...

Higher Arithmetic: Designed for the Use of High Schools, Academies, and Colleges

George Roberts Perkings - 1841 - 252 σελίδες
...and the interest, to find the rate per cent. RULE. Divide the given interest by the interest oftte given principal, for the given time, at 1 per cent....The interest of $100, for 9 months and 10 days, is $3.50. What is the rate per cent. ? In this example we find the interest of $100, for 9 months and...

A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - 1841 - 312 σελίδες
...of the interest for 1 year, is to the given interest, as 1 year is to the time required. Hence the RULE : Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the answer. 2. In what time will $240 gain $4.80, at 6 per cent. ?...

An Elementary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1846 - 258 σελίδες
...$4090.909. PROBLEM III. Given the principal, the time, and the interest, to find the rate per cent. RULE. Divide the given interest by the interest of...The interest of $100, for 9 months and 10 days, is $3.50. What is the rate per cent. ? In this example, we find the interest of $100, for 9 months and...

The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - 1848 - 168 σελίδες
...months (145), the answer. Therefore, IV. Tlte principal, rate and interest being given, tQjind the time. RULE. — Divide the given interest by the interest of the given principal for 1 year at the given rate, and the quotient will be the time m years and decimal ^,arts. 2. If the interest...

An Elemtary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - 1849 - 347 σελίδες
...as many times greater than the interest for one year, as the particular time is greater than 1 year. Hence, we have this RULE. Divide the given interest by the interest of the given principal, for 1 year, at the given rate per cent. EXAMPLES, 1. In what time will $37-13. at 4£ per cent., give $0-7518825...

Putnam's Arithmetic

Rufus Putnam - 1849 - 264 σελίδες
...it must be on interest as many years as there are times $21 in $87.50. Ans. 4 j yrs. = 4 yr. 2 mo. RULE. Divide the given interest by the interest of the given principal for 1 year. 4. A note of $340 amounted to $381.65 ; how long was it on interest, the rate being 6J per...




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