 | Horatio Nelson Robinson - 1845 - 310 σελίδες
...may require, will give the cube root very nearly. By repeating the operation with the root last found as an assumed root, we may obtain results to any degree...; one operation, however, is generally sufficient. 3. What is the cube root of 28 ? An*. 3,03658+ 4. What is the cube root of 26 ? Jins. 2,96249+ 5. What... | |
 | Horatio Nelson Robinson - 1846 - 276 σελίδες
...may require, will give the cube root very nearly. By repeating the operation with the root last found as an assumed root, we may obtain results to any degree...operation, however, is generally sufficient. EXAMPLES. 1. What is the approximate cube root of 120'! Ans. 4.93242+ ; 2. What is the approximate cube root of... | |
 | Horatio Nelson Robinson - 1848 - 354 σελίδες
...may require, will give the cube root very nearly. By repeating the operation with the root last found as an assumed root, we may obtain results to any degree...operation, however, is generally sufficient. EXAMPLES. 1. What is the approximate cube root of 120? Ans. 4-93242+. 2. What is the approximate cube root of 8-5... | |
 | 1851 - 260 σελίδες
...may require, will give the cube root very nearly. By repeating the operation with the root last found as an assumed root, we may obtain results to any degree...; one operation, however, is generally sufficient. 3 What is the cube root of 28 ? Ans. 3.03658 + . 4 What is ftie cube root of 26'? Ans. 2.96249+. 5... | |
 | 1853 - 266 σελίδες
...two roots, and if the last root, or 61, was unknown, this proportion would give it very nearly. v * EXAMPLES. 1. Required the cube root of 66. The cube...similar proportion to the preceding, we have 64X2=128 66 194 Or, 194 APPENDIX. 2X66=132 64 196 : 4 : : 4 : to root of G6. to a correction. 194)8.0000(0.04124... | |
 | Horatio Nelson Robinson - 1854 - 306 σελίδες
...unknown, this proportion would give it very nearly, by giving the difference between the two roots. EXAMPLES. 1. Required the cube root of 66. The cube...taking a similar proportion to the preceding, we have 64X2 = 128 2X66=132 66 64 ARITHMETIC. 194)8,0000(0,04124 776 240 194 460 388 720 Therefore, the cube... | |
 | Horatio Nelson Robinson - 1858 - 372 σελίδες
...nearly. By repeating the operation with the root last found as an assumed root, we may obtain resulte to any degree of exactness ; one operation, however, is generally sufficient. EXAMPLES. 1 • What is the approximate cube root of 120 ? Ans. 4-93242-K 9. What is the approximate cube root... | |
 | Hoy D. Orton - 1866 - 202 σελίδες
...may require, will give the cube root very nearly. By repeating the operation with the root last found as an assumed root, we may obtain results to any degree...is generally sufficient. EXAMPLES. 1. Required the cube*root of 66. The cube root of 64 is 4. Now it is manifest that the cube root of 66 is a little... | |
 | Hoy D. Orton, Warren H. Sadler - 1881 - 316 σελίδες
...to any degree of exactness; one operation, howrvcr, is generally sufficient. EXAMPLES. 1. Eequired the cube root of 66. The cube root of 64 is 4. Now...similar proportion to the preceding, we have 64x2=128 2X66=132 66 64 Or, 194 : 2 : : 4 : to a correction 194)8.0000(0.04124 776 240 194 460 388 720 Therefore... | |
 | Hoy D. Orton, Warren H. Sadler - 1888 - 342 σελίδες
...may require, will give the cube root very nearly. By repeating the operation with the root last found as an assumed root, we may obtain results to any degree...that the cube root of 66 is a little more than 4, »nd by taking a similar proportion to the preceding, we have 128 2*66=132 194 196::4:torootof6& Or,... | |
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By repeating the operation with the root last (blind as an assumed root, we may obtain results to any degree of exactness ; one operation, however, is generally sufficient. EXAMPLES. 1. Required the cube root of 66. The cube root of 64 is 4. Now it is... 
