First Lessons in Geometry: With Practical Applications in Mensuration, and Artificers' Work and MechanicsA.S. Barnes, 1840 - 252 σελίδες |
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Σελίδα 92
... inches and six - tenths . Place one foot of the dividers at 2 on the left , and ex- tend the other to , 6 , which marks the sixth of the small divisions : the dividers will then embrace the required distance . PROBLEM V. To lay down ...
... inches and six - tenths . Place one foot of the dividers at 2 on the left , and ex- tend the other to , 6 , which marks the sixth of the small divisions : the dividers will then embrace the required distance . PROBLEM V. To lay down ...
Σελίδα 94
... inches , the scale being 40 feet to the inch : then , 3,55 × 40 = 142 feet , the length of the line . 2. If the length of a line on the paper is 6,25 inches , and the scale be one of 30 feet to the inch , what is the true length of the ...
... inches , the scale being 40 feet to the inch : then , 3,55 × 40 = 142 feet , the length of the line . 2. If the length of a line on the paper is 6,25 inches , and the scale be one of 30 feet to the inch , what is the true length of the ...
Σελίδα 122
... feet 4 inches ? ( See Arithmetic , § 171 ) . Ans . 69 ft . 5 ' 4 " . 4. What is the content of a square field whose side is 46 rods ? Ans . 13 A. 0 R. 36 P. 5. What is the area of a square whose side is 4769 yards ? Ans . 22743361 sq . yds ...
... feet 4 inches ? ( See Arithmetic , § 171 ) . Ans . 69 ft . 5 ' 4 " . 4. What is the content of a square field whose side is 46 rods ? Ans . 13 A. 0 R. 36 P. 5. What is the area of a square whose side is 4769 yards ? Ans . 22743361 sq . yds ...
Σελίδα 123
... inches , and altitude 3 feet 6 inches ? Ans . 27 sq . ft . 1 ' 6 " . 9. To find the area of a rectangle D ABCD , of which the base AB = 45 yards , and the altitude AD = 15 yards . Here we simply multiply the base by the altitude , and ...
... inches , and altitude 3 feet 6 inches ? Ans . 27 sq . ft . 1 ' 6 " . 9. To find the area of a rectangle D ABCD , of which the base AB = 45 yards , and the altitude AD = 15 yards . Here we simply multiply the base by the altitude , and ...
Σελίδα 131
... feet 6 inches , and 18 feet 9 inches , and the perpendicular distance between them 10 feet and 5 inches ? Ans . 230 sq . ft . 5 ' 7 " . 4. Required the area of a trapezoid whose parallel sides are 20,5 and 12,25 , and the perpendicular ...
... feet 6 inches , and 18 feet 9 inches , and the perpendicular distance between them 10 feet and 5 inches ? Ans . 230 sq . ft . 5 ' 7 " . 4. Required the area of a trapezoid whose parallel sides are 20,5 and 12,25 , and the perpendicular ...
Άλλες εκδόσεις - Προβολή όλων
Συχνά εμφανιζόμενοι όροι και φράσεις
12 feet 20 feet acres altitude bisect bounded by Planes breadth called centre of gravity chord circular sector circumfer circumference cone convex surface cubic feet cubic foot cubic inches cylinder decimal diagonals diameter distance divide draw equilateral triangle EXAMPLES Explain the manner feet 6 inches figure find the area find the solidity frustum given angle given line given point gles half hypothenuse intersect line be drawn linear unit lower base manner of inscribing Mensuration of Surfaces multiplied number of square parallel planes parallelogram parallelopipedon pentagon pentagonal pyramid perpendicular Practical Geometry.-Problems PROBLEM pulley pyramid radius rectangle regular polygon regular solids Required the area rhombus right angled triangle Round Bodies RULE scale of equal secant line segment similar polygons similar triangles slant height solid content solid feet Solids bounded specific gravity sphere square feet square yards straight line tangent thickness upper base weight
Δημοφιλή αποσπάσματα
Σελίδα 20 - Every circumference of a. circle, whether the circle be large or small, is supposed to be divided into 360 equal parts called degrees. Each degree is divided into 60 equal parts called minutes, and each minute into 60 equal parts called seconds.
Σελίδα 32 - The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R.
Σελίδα 40 - Similar triangles are to each other as the squares described on their homologous sides. Let ABC, DEF be two similar triangles...
Σελίδα 82 - A zone is a portion of the surface of a sphere included between two parallel planes.
Σελίδα 235 - An equilibrium is produced in all the levers, when the weight multiplied by its distance from the fulcrum is equal to the product of the power multiplied by its distance from the fulcrum. That...
Σελίδα 84 - The convex surface of a cylinder is equal to the circumference of its base multiplied by its altitude.
Σελίδα 34 - The area of a triangle is equal to half the product of the base and height.
Σελίδα 35 - If two triangles have two sides and the included angle of the one, equal to two sides and the included angle of the other, each to each, the two triangles will be equal in all their parts." Axiom 1. "Things which are equal to the same thing, are equal to each other.
Σελίδα 20 - For this purpose it is divided into 360 equal parts, called degrees, each degree is divided into 60 equal parts called minutes, and each minute into 60 equal parts called seconds. The degrees, minutes, and seconds, are marked thus, °, ', " ; and 9° 18' 10", are read, 9 degrees, 18 minutes, and 10 seconds.
Σελίδα 83 - The surface of a sphere is equal to the product of its diameter by the circumference of a great circle.