 | Jeremiah Day - 1815 - 388 σελίδες
...surface of a. hemisphere is equal to the product of its radius into the circumference of its base ; and the surface of a sphere is equal to the product of its diameter into its circumference. Cor. T . From this demonstration it follows, that the surface of any segment... | |
 | Adrien Marie Legendre - 1819 - 574 σελίδες
...circle. This axis FG will be at the same time the diameter of the circumscribed circle. THEOREM. 535. The surface of a sphere is equal to the product of...its diameter by the circumference of a great circle. Demonstration. 1. We say that the diameter of a sphere multiplied by the circumference of a great circle... | |
 | Adrien Marie Legendre - 1825 - 276 σελίδες
...circle. This axis FG will be at the same time the diameter of the circumscribed circle, • THEOREM. 535. The surface of a sphere is equal to the product of...its diameter by the circumference of a great circle. Demonstration. 1. We say that the diameter of a sphere multiplied by the circumference of a great circle... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 σελίδες
...circle. This axis FG will be at the same time the diameter of the circumscribed circle. THEOREM. 535. The surface of a sphere is equal to the product of...its diameter by the circumference of a great circle. measure of^the surface of a greater sphere. For, if it be possiFig. 263. ble, let AB x circ. AC (Jig.... | |
 | Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - 1828 - 598 σελίδες
...half the sum of all the parallel sides, or half the sum of the two circumferences. QED Theorem 535. ' The surface of a sphere is equal to the product of...diameter by the circumference of a great circle.' This is incuded in the preceding corollary. ' The entire surface described by the revolution of a semipolygon... | |
 | Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - 1828 - 598 σελίδες
...half the sum of all the parallel sides, or half the sum of thetwo circumferences. QED Theorem 535. ' The surface of a sphere is equal to the product of...diameter by the circumference of a great circle.' This is incuded in the preceding corollary. ' The entire surface described by the revolution of a semipolygon... | |
 | Adrien Marie Legendre - 1828 - 346 σελίδες
...circle. This axis FG xvill at the same time be the diameter of the circumscribed circle. THEOREM. 535. The surface of a sphere is equal to the product of...its diameter by the circumference of a great circle. We shall first shew, that the diameter of a sphere multiplied by the circumference of its great circle... | |
 | Jeremiah Day - 1831 - 418 σελίδες
...surface of a hemisphere is equal to the product of its radius into the circumference of its base; and the surface. of a sphere is equal to the product of its diameter into its circumference. Cor. 1. From this demonstration it follows, that the surface of any segment... | |
 | Jeremiah Day - 1831 - 394 σελίδες
...surface of a hemisphere is equal to the product of its radius into the circumference of its base ; and the surface of a sphere is equal to the product of its diameter into its circumference. Cor. 1. From this demonstration it follows, that the surface of any segment... | |
 | Adrien Marie Legendre - 1836 - 394 σελίδες
...described by ED + DC, is equal to (HI + IP) xcirc. ON, or equal to HP x circ. ON. PROPOSITION X. THEOREM. The surface of a sphere is equal to the product of...diameter by the circumference- of a great circle. Let ABCDE be -a semicircle. Inscribe in it any regular semi-polygon, and from the centre O draw OF... | |
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The surface of a sphere is equal to the product of its diameter by the circumference of a great circle. 
